2 ln (1+√√y) = 2 ln (1+√√x) + In C n{(1 + √y)²} = ln {C(1 + √@)²}
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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I do not understand what they did from the first to second line
![2 ln (1 + √y) = 2 ln (1+√√x) + In C
In { (1 + √y)²} = ln {C(1 + √π)²}
(1 + √y)² = C(1 + √√x) ²
1+√y = C₁ (1+√x)
Further, simplify the above equation,
√y = C₁ (1+√√x) – 1
= [C₁ (1 + √√x) − 1]²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F21e8b9dc-8a46-44e8-b3f1-f32e58de6fd1%2F7481e4d5-a2e9-4ef8-96f1-96d3f9be144f%2F2nk312p_processed.png&w=3840&q=75)
Transcribed Image Text:2 ln (1 + √y) = 2 ln (1+√√x) + In C
In { (1 + √y)²} = ln {C(1 + √π)²}
(1 + √y)² = C(1 + √√x) ²
1+√y = C₁ (1+√x)
Further, simplify the above equation,
√y = C₁ (1+√√x) – 1
= [C₁ (1 + √√x) − 1]²
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I unfortunately do not follow. How does ln turn into log?
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