(2) Let A € Rmxn and let à be a solution of the least squares problem Az = b. Show that a vector y ER" will also be a solution if and only if y = 2 + z, for some vector z € N(A). [HINT: N(ATA) = N(A)].

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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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2.

**Problem Statement:**

Let \( A \in \mathbb{R}^{m \times n} \) and let \( \hat{x} \) be a solution of the least squares problem \( Ax = b \). Show that a vector \( y \in \mathbb{R}^n \) will also be a solution if and only if \( y = \hat{x} + z \), for some vector \( z \in N(A) \). [HINT: \( N(A^T A) = N(A) \)].

**Detailed Explanation:**

- **Vector Spaces:**
  - \( \mathbb{R}^{m \times n} \): The space of all \( m \times n \) matrices with real numbers.
  - \( \mathbb{R}^n \): The space of all \( n \)-dimensional vectors with real numbers.
  - \( N(A) \): The null space of the matrix \( A \), which is the set of all vectors \( x \) such that \( Ax = 0 \).
  - \( N(A^T A) \): The null space of the matrix \( A^T A \), where \( A^T \) is the transpose of \( A \).

- **Least Squares Problem:**
  - The least squares problem seeks to find a vector \( \hat{x} \) such that \( Ax \approx b \), minimizing the residual \( \|Ax - b\| \).

- **Solution Characterization:**
  - The problem asks to show that any vector \( y \) that is also a solution to the least squares problem can be written as \( \hat{x} + z \), where \( z \) is in the null space of \( A \).

- **Hint Utilization:**
  - The hint provided states that the null space of \( A^T A \) is the same as the null space of \( A \), i.e., \( N(A^T A) = N(A) \).

**Steps to Solution:**

1. **Understanding Null Spaces:**
   - The null space \( N(A) \) consists of all vectors \( z \) such that \( Az = 0 \).
   - If \( y \) is another solution, \( A\hat{x} ≈ b \) and \( Ay ≈ b \).
   
2. **Formulating y
Transcribed Image Text:**Problem Statement:** Let \( A \in \mathbb{R}^{m \times n} \) and let \( \hat{x} \) be a solution of the least squares problem \( Ax = b \). Show that a vector \( y \in \mathbb{R}^n \) will also be a solution if and only if \( y = \hat{x} + z \), for some vector \( z \in N(A) \). [HINT: \( N(A^T A) = N(A) \)]. **Detailed Explanation:** - **Vector Spaces:** - \( \mathbb{R}^{m \times n} \): The space of all \( m \times n \) matrices with real numbers. - \( \mathbb{R}^n \): The space of all \( n \)-dimensional vectors with real numbers. - \( N(A) \): The null space of the matrix \( A \), which is the set of all vectors \( x \) such that \( Ax = 0 \). - \( N(A^T A) \): The null space of the matrix \( A^T A \), where \( A^T \) is the transpose of \( A \). - **Least Squares Problem:** - The least squares problem seeks to find a vector \( \hat{x} \) such that \( Ax \approx b \), minimizing the residual \( \|Ax - b\| \). - **Solution Characterization:** - The problem asks to show that any vector \( y \) that is also a solution to the least squares problem can be written as \( \hat{x} + z \), where \( z \) is in the null space of \( A \). - **Hint Utilization:** - The hint provided states that the null space of \( A^T A \) is the same as the null space of \( A \), i.e., \( N(A^T A) = N(A) \). **Steps to Solution:** 1. **Understanding Null Spaces:** - The null space \( N(A) \) consists of all vectors \( z \) such that \( Az = 0 \). - If \( y \) is another solution, \( A\hat{x} ≈ b \) and \( Ay ≈ b \). 2. **Formulating y
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