Determine the member end moments for the frame shown in Fig. 16.13(a) by using the moment-distribution method. 2 k/ftE1= 1,600 in.4 D1= 1,600 in.-10 ft+ 40 k-10 ftAB30 ft-30 ft-E = 29,000 ksi(a) Frame1%3D800 in.4/ = 800 in.4

Answered: 2 k/ft E 1= 1,600 in.4 D 1= 1,600 in.-…

2 k/ft E 1= 1,600 in.4 D 1= 1,600 in.- 10 ft + 40 k- 10 ft A B 30 ft -30 ft- E = 29,000 ksi (a) Frame 1%3D800 in.4 / = 800 in.4

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Determine the member end moments for the frame shown in Fig. 16.13(a) by using the moment-distribution method.

2 k/ft
E
1= 1,600 in.4 D
1= 1,600 in.-
10 ft
+ 40 k-
10 ft
A
B
30 ft
-30 ft-
E = 29,000 ksi
(a) Frame
1%3D800 in.4
/ = 800 in.4

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