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(2) j0.125 j0.4 j0.25. bj0.2 j0.25 (1) (4) 3 j0.1 (3) j0.1 : j0.2 j0.2

(2) j0.125 j0.4 j0.25. bj0.2 j0.25 (1) (4) 3 j0.1 (3) j0.1 : j0.2 j0.2

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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(2) j0.25. j0.125 j0.2 j0.25 j0.4 (3) · (4) j0.1 (1) j0.1 j0.2 j0.2
Transcribed Image Text:(2) j0.25. j0.125 j0.2 j0.25 j0.4 (3) · (4) j0.1 (1) j0.1 j0.2 j0.2
(a) Calculate Ybus using the fact that Yi is the sum of all admittances connected to bus i and Y¡j is the negative of the admittance connecting bus i to bus j.
Transcribed Image Text:(a) Calculate Ybus using the fact that Yi is the sum of all admittances connected to bus i and Y¡j is the negative of the admittance connecting bus i to bus j.
Expert Solution
Step 1

Let us convert all impedances to admittance form first.

y12 = 1z12 = 1j 0.125 = - j 8

y13 = 1z13 = 1j 0.25 = - j 4

y14 = 1z14 = 1j 0.4 = - j 2.5

y23 = 1z23 = 1j 0.25 = - j 4

y24 = 1z24 = 1j 0.2 = - j 5

y33 = 1z33 = 1j 0.1 + j 0.2 = 1j 0.3 = -j 103

y44 = 1z44 = 1j 0.1 + j 0.2 = 1j 0.3 = -j 103

 

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