Explain in your own words what the code in 2iii does step by step. 2 ii)int a =5;//L1//L2for (int i = 5; i <= 6; i++){а %3Dа + 3;System.out.println(a);}а %3D а + 2;//L3//L4//L5I|

Answered: 2 iii) int a = 5; //L1 //L2 for(int i =…

Engineering

Computer Science

2 iii) int a = 5; //L1 //L2 for(int i = 5; i <= 6; i++) { а %3D а + 3; System.out.println(a); //L3 //L4 a = a + 2; //L5

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation). This is accomplished by taking the remainder of the division and dividing it by the original divisor. If the new quotient is higher than or equal to one, multiply it by one.Otherwise, leave the original quotient alone.In MIPS assembly, implement integer division using rounding (rather than truncation).…
Matlab Question
please answer this. thanks a. Give analysis of the running time (Big-Oh will do) and the space complexity. b. Implement the code in C language and give the running time for threevalues of N (N must be > 5). c. Compare your analysis with the actual running times. (3.) sum = 0; for( i = 0; i < n; ++i ) for( j = 0; j < i * i; ++j ) for( k = 0; k < j; ++k ) ++sum;
Please do it in c++ as soon as possible. From the get go, Mr. Chanek has a grid an of size n×m Each phone (x,y) contains a number ax,y demonstrating the course of how the ball will move. ax,y=1 — the ball will move aside (the accompanying cell is (x,y+1)); ax,y=2 — the ball will move to the base (the accompanying cell is (x+1,y)); ax,y=3 — the ball will move aside (the accompanying cell is (x,y−1)). Each time a ball leaves a cell (x,y), the number ax,y will change to 2. Mr. Chanek will drop k balls progressively, each start from the primary line, and on the c1,c2,… ,ck-th (1≤ci≤m) segments. Choose in what segment each ball will end up in (position of the ball in the wake of leaving the grid). Input The chief line contains three whole numbers n, m, and k (1≤n,m≤1000, 1≤k≤105) — the size of the cross section and the amount of balls dropped by Mr. Chanek. The I-th of the accompanying n lines contains m numbers ai,1,ai,2,… ,ai,m (1≤ai,j≤3). It will satisfy ai,1≠3 and ai,m≠1. The…
In C++
Suppose your friend Thomas goes on a business meeting with Elon Musk. He knows that Elon Musk loves numbers, so as a gift he is going to bring boxes with numbers X, X+1, X+2, ..., N written on it. Elon is fascinated with divisors of prime number. That's why he is going to give one minute of his time to each such number on the boxes. Now you have to develop a C code to find out the amount of time that will Elon give to Thomas. Test Case Result 1 10 1 17
Please Answer this in C++ only Devo is learning Combinatorics in his college. He finds it very interesting to calculate number of ways of going to point (c, d) from point (a, b) in co-ordinate plane. We can take horizontal and vertical steps only and cannot visit at a point twice. In a step, you can move one unit only. We have to reach to the point (c, d) from the point (a, b) using abs(a-c) + abs(b-d) steps only. Devo has two sets of points. Set A contains points having X co-ordinate 0 and Y co- ordinates varying from 1 to N (both inclusive). Set B contains points having X co- ordinate K and Y co-ordinates varying from 1 to N (both inclusive). Both sets contain N number of integral points. He wants to calculate the sum of number of ways to going to each point of set B from each point of set A. As the answer can be large, print it modulo 1000000007. Input 2 22 45 Output 8 236