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2 H KOH (catalytic) EtOH 78°C

2 H KOH (catalytic) EtOH 78°C

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How do I find the Major product

The image shows a chemical reaction schematic. On the left side, there are two reactants: 1. Cyclohexanone represented by a six-membered ring with a carbonyl group (C=O). 2. Two molecules of 2,2-dimethylcyclopentanone, represented by a five-membered ring with a carbonyl group and two methyl groups attached to the same carbon atom. An arrow points to the right, indicating the reaction process. Above the arrow, the text reads "KOH (catalytic)," indicating that potassium hydroxide is used as a catalyst. Below the arrow, the conditions "EtOH" and "78 °C" are listed, specifying that the reaction takes place in ethanol at a temperature of 78 degrees Celsius.
Transcribed Image Text:The image shows a chemical reaction schematic. On the left side, there are two reactants: 1. Cyclohexanone represented by a six-membered ring with a carbonyl group (C=O). 2. Two molecules of 2,2-dimethylcyclopentanone, represented by a five-membered ring with a carbonyl group and two methyl groups attached to the same carbon atom. An arrow points to the right, indicating the reaction process. Above the arrow, the text reads "KOH (catalytic)," indicating that potassium hydroxide is used as a catalyst. Below the arrow, the conditions "EtOH" and "78 °C" are listed, specifying that the reaction takes place in ethanol at a temperature of 78 degrees Celsius.
Expert Solution
Step 1: Interpretation of given problem

Given is one ketone and 2 aldehyde compounds.

The reagent  is base KOH .

The solvent used is ethanol.


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