2 х+ 3x —8 - What is the limit lim X 2- x2 - 4 O (-) infinity O DNE O + infinity

Q: x²-2x-3 lim a. (x-3)3 2-2r-3 x-3 (x-3)' x² - 2x-3 b. lim x² - 2x-3 lim 33 (x-3)3 c.

A: x→3+ limx2-2x-3(x-3)3=x→3+lim(x-3)(x+1)(x-3)3=x→3+limx+1(x-3)2=∞

Q: 3- Vx Determine lim- x+4 x-9

A: Given limx→43-xx-9

Q: Find the limit

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Q: Apply Maclaurln's Serles to Show (-1)*-1,2=-2) 2(n – 1)1 cos X=

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Q: 2x + lim X→-2 X + 2 X + 2

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Q: Q2 Q2) Evaluate the limit at x-1 for: x3 + 2x2 - x-2 f(x) = x2 6x + 5 Your answer

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Q: Find the limit 3x lim0 tan(5x)

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Q: Calculate lim x-2 x+2 Evaluate the Limit

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Q: iz?-z- lim- z2-1 %3D i0 -i O 00

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Q: h) lim x* +x?- 2 I+x+x+x

A: Here we have to find the limit of given function. We can divide it in two function , one in…

Q: Evaluate the limit of the function below x² – 4| lim, 'x→2 х - 2 O The limit does not exist O 1 O 2

A: limx→2x2-4x-2consider the function x=x,x≥0-x,x<0

Q: x²+3x+2 b) lim x-1 x²-x-2

A: given limit

Q: 8+x-4x? Lim\ belowr → 0∞ V6+x²+7x* O a. -4/7 O b. 4/7 O c. 4//7 O d. -4/7

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Q: limit     2-x/4-x x-->4

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Q: x*-2x2-x с- lim x-2 , х 2 2 х2-4

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Q: 4ー npaメ lim メ-2

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Q: lim (r -2)11/(3-z)

A: Firstly, we take log on both sides and use the result that  log m^n=nlogm.

Q: csc 2x lim *+0 csc 3x O O O O 23 N|C I N|W 3 2 23

A: Topic - limits We are given, limx→0-csc 2xcsc 3xwe know thatlimx→0sin xx=1anscsc x =1sin x

Q: x- 2 Find Lim x-2 x*-16

A: To evaluate the given limit.

Q: 1-x 6. lim X-3 X+3

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Q: Find the limit

A: We will find the limit by substitution

Q: x' +3x +3x+1 Find lim x1 2x +3x² – 1

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Q: can you find the limit, and if it doesn't exist can you put DNE

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Q: х2+2х-3 lim X→-1 х2-1

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Q: Find the limit

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Q: 1 lim 2 -1 x* -1,

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Q: Find the limit. Use 5r3+ r2 _ 2 (b) lim H118 3 – 1.5r2 l'Hospital's Role

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Q: im -3 1 x+5 8 x-3 ►

A: