2- Given: Poil = 800 kg/m³ PHg = 13,600 kg/m² Given: Z₁=0.6m Z₂=0.73m Z3=0.26m hm = 0.13m " Z₁ = = 100 mm Z₂=250mm h= 90 mm e KN 4/₂0 = 1,00 Z₁ ↓ Calculate: • The pressure drop AP (= P.-P.) The head loss Ah (express in terms of meters of H₂O) 2X .000 ку m3 . Calculate the pressure drop AP (=P₁-P₁₂) kautta Z₂ ↓ hm нд 2 " • Express OP in terms of head loss Dh ( in meters H₂₂0) -air x2 Water

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Please explain how to do each step, thanks!

1-
2-
Given:
Poil = 800 kg/m³
PHg = 13,600 kg/m²
.
3
Given :
Calculati:
Z₁=0.6m
Z₂=0.73m
Z3=0.26m
"
hm²
= 0.13m
Z;=
Z₁
= 100mm
k
ZX
Z
oil
Z₂
↓
The pressure drop AP (= P.-P)
The head loss sh (express in terms of meters of H₂O)
·hm
Hg
Z₂=250mm
h = 90 mm
e
4/₂0 = 1,000 kg
m3
Calculate the pressure drop AP (=P₁-P₂)
• Express DP in terms of head loss Dh ( in meters H₂0)
-air
tr
Water
Transcribed Image Text:1- 2- Given: Poil = 800 kg/m³ PHg = 13,600 kg/m² . 3 Given : Calculati: Z₁=0.6m Z₂=0.73m Z3=0.26m " hm² = 0.13m Z;= Z₁ = 100mm k ZX Z oil Z₂ ↓ The pressure drop AP (= P.-P) The head loss sh (express in terms of meters of H₂O) ·hm Hg Z₂=250mm h = 90 mm e 4/₂0 = 1,000 kg m3 Calculate the pressure drop AP (=P₁-P₂) • Express DP in terms of head loss Dh ( in meters H₂0) -air tr Water
Expert Solution
Step 1

Given: 

z1=0.6 m

z2=0.73 m

hm=0.13 m

Density of the oil, doil=800 kg/m3

Density of the mercury dhg=13600 kg/m3

Density of the water, dh2o=1000 kg/m3

Hydraulic pressure at any depth(z) is determined by the formula, p=d×g×z

Where d is density of the fluid, g is 9.81 m/s2, and z is the depth of the point at which the pressure is to be determined.

Let the pressure at point x1 =P1

Let the pressure at point x2 =P2

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