2- Given: Poil = 800 kg/m³ PHg = 13,600 kg/m² Given: Z₁=0.6m Z₂=0.73m Z3=0.26m hm = 0.13m " Z₁ = = 100 mm Z₂=250mm h= 90 mm e KN 4/₂0 = 1,00 Z₁ ↓ Calculate: • The pressure drop AP (= P.-P.) The head loss Ah (express in terms of meters of H₂O) 2X .000 ку m3 . Calculate the pressure drop AP (=P₁-P₁₂) kautta Z₂ ↓ hm нд 2 " • Express OP in terms of head loss Dh ( in meters H₂₂0) -air x2 Water
2- Given: Poil = 800 kg/m³ PHg = 13,600 kg/m² Given: Z₁=0.6m Z₂=0.73m Z3=0.26m hm = 0.13m " Z₁ = = 100 mm Z₂=250mm h= 90 mm e KN 4/₂0 = 1,00 Z₁ ↓ Calculate: • The pressure drop AP (= P.-P.) The head loss Ah (express in terms of meters of H₂O) 2X .000 ку m3 . Calculate the pressure drop AP (=P₁-P₁₂) kautta Z₂ ↓ hm нд 2 " • Express OP in terms of head loss Dh ( in meters H₂₂0) -air x2 Water
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Please explain how to do each step, thanks!

Transcribed Image Text:1-
2-
Given:
Poil = 800 kg/m³
PHg = 13,600 kg/m²
.
3
Given :
Calculati:
Z₁=0.6m
Z₂=0.73m
Z3=0.26m
"
hm²
= 0.13m
Z;=
Z₁
= 100mm
k
ZX
Z
oil
Z₂
↓
The pressure drop AP (= P.-P)
The head loss sh (express in terms of meters of H₂O)
·hm
Hg
Z₂=250mm
h = 90 mm
e
4/₂0 = 1,000 kg
m3
Calculate the pressure drop AP (=P₁-P₂)
• Express DP in terms of head loss Dh ( in meters H₂0)
-air
tr
Water
Expert Solution

Step 1
Given:
Density of the oil,
Density of the mercury
Density of the water,
Hydraulic pressure at any depth(z) is determined by the formula,
Where d is density of the fluid, g is , and z is the depth of the point at which the pressure is to be determined.
Let the pressure at point
Let the pressure at point
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