Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![### Geometric Sequences: Sum Calculation
#### Problem Statement
Find the sum of the indicated number of terms of the geometric sequence.
\[ -4, 12, -36, \ldots ; \quad n = 4 \]
(Note: The fourth term is not explicitly given and needs to be calculated.)
#### Explanation
The problem involves finding the sum of the first four terms of a geometric sequence. A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio.
Given:
- First term (\(a_1\)) = \(-4\)
- Common ratio (\(r\)) can be found using the second term divided by the first term: \( r = \frac{12}{-4} = -3 \)
- Number of terms (\(n\)) = 4
#### Steps to Calculate the Sum
To find the sum \(S_n\) of the first \(n\) terms of a geometric sequence, you can use the formula:
\[ S_n = a_1 \frac{1-r^n}{1-r} \]
For the given sequence:
1. \(a_1 = -4\)
2. \( r = -3 \)
3. \( n = 4 \)
First, calculate \(r^n\):
\[ r^n = (-3)^4 = 81 \]
Applying the sum formula:
\[ S_4 = -4 \frac{1 - (-3)^4}{1 - (-3)} = -4 \frac{1 - 81}{1 + 3} = -4 \frac{1 - 81}{4} = -4 \frac{-80}{4} = -4 \times (-20) = 80 \]
Therefore, the sum of the first four terms is \(80\).
#### Final Answer
\[ \boxed{80} \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F667c2432-c02d-4ad1-9d8f-1347249c5b46%2F26565cd8-d1b4-4f08-8c74-bec24d595339%2Fb1yt51d.jpeg&w=3840&q=75)
Transcribed Image Text:### Geometric Sequences: Sum Calculation
#### Problem Statement
Find the sum of the indicated number of terms of the geometric sequence.
\[ -4, 12, -36, \ldots ; \quad n = 4 \]
(Note: The fourth term is not explicitly given and needs to be calculated.)
#### Explanation
The problem involves finding the sum of the first four terms of a geometric sequence. A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio.
Given:
- First term (\(a_1\)) = \(-4\)
- Common ratio (\(r\)) can be found using the second term divided by the first term: \( r = \frac{12}{-4} = -3 \)
- Number of terms (\(n\)) = 4
#### Steps to Calculate the Sum
To find the sum \(S_n\) of the first \(n\) terms of a geometric sequence, you can use the formula:
\[ S_n = a_1 \frac{1-r^n}{1-r} \]
For the given sequence:
1. \(a_1 = -4\)
2. \( r = -3 \)
3. \( n = 4 \)
First, calculate \(r^n\):
\[ r^n = (-3)^4 = 81 \]
Applying the sum formula:
\[ S_4 = -4 \frac{1 - (-3)^4}{1 - (-3)} = -4 \frac{1 - 81}{1 + 3} = -4 \frac{1 - 81}{4} = -4 \frac{-80}{4} = -4 \times (-20) = 80 \]
Therefore, the sum of the first four terms is \(80\).
#### Final Answer
\[ \boxed{80} \]
Expert Solution

Step 1
Consider the given series.
Step 2
Here,
First term = - 4
n = 4
Common Ratio = - 3
Step by step
Solved in 4 steps with 3 images

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