2- Find the output of the following for loop statements. A- for (int i=0; i<=10; i++) Cout<<"*"<<"\n";
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- Trace the following and select which output matches your output from your trace: #include <iostream> using namespace std; int main() { int x, y; int *p = &x; int *q = &y; x = 62; y = 38; *p = 55; cout << x << " " << y << endl; cout << *q << " " << *p << endl; return 0; }Q3/ Find the output of the following program . # include main() { int n,m,y. n=4; m=5; y=++n + --m +n++ + n++n_;#include using namespace std; int main() { int stop; int result; int n; } cin >> stop; result = 0; Type the program's output for (n = 0; n stop) { cout << "n=" << n; cout << endl; break; } } cout << result << endl; return 0; Input 7 OutputPlease code in C++Direction: Given the source code in column one. Write their expected output in column two. #include using namespace std; int main() { for (int i = 1; i using namespace std; int main() { int num, sum; sum = 0; cout > num; for (int count = 1; count using namespace std; int main () { // for loop execution for( int a = 10; a < 20; a = a + 1 ) { cout << "value of a: " << a << endl; } return 0; }Using the following description, please replace the return line in C code; /* * logicalShift: logical shift x to the right by n, * where 0 <= n <= 31 * Examples: * logicalShift(0xFFFFFFFF,0) = 0xFFFFFFFF * logicalShift(0xFFFFFFFF,1) = 0x7FFFFFFF * logicalShift(0xFFFFFFFF,2) = 0x3FFFFFFF * logicalShift(0xFFFFFFFF,3) = 0x1FFFFFFF * logicalShift(0xFFFFFFFF,4) = 0x0FFFFFFF * logicalShift(0xFFFFFFFF,8) = 0x00FFFFFF * logicalShift(0xFFFFFFFF,12) = 0x000FFFFF * Legal ops: ! ~ & ^ | + << >> * Max ops: 20 * Rating: 3 * Hints/notes: * */ int logicalShift(int x, int n) { return 2 } You cannot: 1. Use any control constructs such as if, do, while, for, switch, etc. 2. Define or use any macros. 3. Define any additional functions in this file. 4. Call any functions. 5. Use any other operations, such as &&, ||, -, or ?:, not listed in the the "Legal ops" list for the function. 6. Use any form of casting. 7. Use any data type other than int.ii) Given the following fragment of code: for(int i = 1; i#include void main() { while (x < 5 && y < 6) { X = x + 1; y = y + 2; cout << "X: " << X << " "; cout << "Y: "<< y << endl; } Run the program to detect if there is an errors Select one: True False <Use For loop please C++ given code /* Cipher Lab using C strings */ /* Running the program looks like:Enter some lower-case text: helloShifting 0 gives: helloShifting 1 gives: ifmmpShifting 2 gives: jgnnqShifting 3 gives: khoorShifting 4 gives: lippsShifting 5 gives: mjqqtShifting 6 gives: nkrruShifting 7 gives: olssvShifting 8 gives: pmttwShifting 9 gives: qnuuxShifting 10 gives: rovvyShifting 11 gives: spwwzShifting 12 gives: tqxxaShifting 13 gives: uryybShifting 14 gives: vszzcShifting 15 gives: wtaadShifting 16 gives: xubbeShifting 17 gives: yvccfShifting 18 gives: zwddgShifting 19 gives: axeehShifting 20 gives: byffiShifting 21 gives: czggjShifting 22 gives: dahhkShifting 23 gives: ebiilShifting 24 gives: fcjjmShifting 25 gives: gdkkn*/ #include <iostream>#include <iomanip>#include <cctype> using namespace std; // Global constantsconst int MaxWordSize = 81; // 80 characters + 1 for NULL // Given an array of characters and a shift value:// shift each character…#include<stdio.h> void main(){// variables to store input values for account balance and interest ratefloat balance, rate;// variables to store option and choice inputint option, choice;int i, j; // loop counters // outer loop to allows the user to repeat this calculation for a new balance and interest ratewhile(choice != 0){// asking and storing user inputprintf("Bank Account Balance: ");scanf("%f", &balance);printf("Interest Rate: ");scanf("%f", &rate); // printing mod menu and storing input for thatprintf("Mode Menu\n [1] Annually\n [2] Monthly\n");printf("Option: ");scanf("%d", &option); // if selected option is 1if(option == 1){// printing mode selectedprintf("Annually Interest\n");// for 5 yearsfor(i=1; i<=5; i++){// computing balance by adding interestbalance = balance + balance*rate/100.0;// printing balanceprintf("Bank Account Balance in Year %d: %.2f\n", i, balance);}}// if option 2 is selectedelse if(option == 2){// printing mode selectedprintf("Monthly…C++9- The output of the following program is:- * DO 1 K = 2,4 DO 2 M= 1,4, -2 PRINT*, K+1 ,M PRINT*, K , M+1 PRINT*, K , M 1 ENDRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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