2 Find the global (absolute) max/min for f(x) = x² f(x) = x² - 4x on the interval [0,3]. global max at x = O, global min at X = 2 global max at x = O, global min at X = 3 global max at x = 2, global min at X = 0 global max at x = 3, global min at x = 0 If f is not continuous at x = C, then a local (relative) max/min may not exist at x = C. True False

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