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2 Chapter 2 Exercise: Implementing Loops 1. You may use the source code template in h3.s found in the assignment zip archive as a starting point. Let lower and upper be two positive integers with 1 ≤ lower, upper ≤ 10³ and lower ≤ upper. Let a and b be two positive integers with lower ≤ a,b ≤ upper and a ≤ b. Let x =a b. For all pairs of a and b satisfying the specified conditions, find and print the maximal value of x. For example, suppose lower = 10₁0 and upper = 1310- The algorithm will compute x for each a, b pair where 1010 max then max - x end for end for return max end function max_xor function main ( unsigned int lower, max, upper SysPrintStr ("Enter lower?") lower SysReadInt() SysPrintStr ("Enter upper?") upper- SysReadInt () max-max_xor (lower, upper) SysPrintInt (max) SysExit ( end function main

2 Chapter 2 Exercise: Implementing Loops 1. You may use the source code template in h3.s found in the assignment zip archive as a starting point. Let lower and upper be two positive integers with 1 ≤ lower, upper ≤ 10³ and lower ≤ upper. Let a and b be two positive integers with lower ≤ a,b ≤ upper and a ≤ b. Let x =a b. For all pairs of a and b satisfying the specified conditions, find and print the maximal value of x. For example, suppose lower = 10₁0 and upper = 1310- The algorithm will compute x for each a, b pair where 1010 max then max - x end for end for return max end function max_xor function main ( unsigned int lower, max, upper SysPrintStr ("Enter lower?") lower SysReadInt() SysPrintStr ("Enter upper?") upper- SysReadInt () max-max_xor (lower, upper) SysPrintInt (max) SysExit ( end function main

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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2 Chapter 2 Exercise: Implementing Loops 1. You may use the source code template in h3.s found in the assignment zip archive as a starting point. Let lower and upper be two positive integers with 1 ≤ lower, upper ≤ 10³ and lower ≤ upper. Let a and b be two positive integers with lower ≤ a,b ≤ upper and a ≤ b. Let x =ab. For all pairs of a and b satisfying the specified conditions, find and print the maximal value of x. For example, suppose lower = 10₁0 and upper = 1310. The algorithm will compute x for each a, b pair where 1010 <a,b≤13₁0 anda<b, x = 1010 1010 1010₂1010₂=0000₂ 010x = 1010 01110101021011₂=0001₂= 110x= 1010 12 10 = 1010₂1100₂ = 0110₂=610x = 1010 1310 = 101021101₂-0111₂ = 710 X = 11101110 1011₂01011₂ - 0000₂= 010x = 11101210 = 1011₂2 1100₂ 0111₂= 710x = 1110 13 ₁0 = 1011₂1101₂= 0110₂= 6₁0x = 1210 1210 1100₂1100₂ = 0000₂=0₁0x=12101310 = 1100₂1101₂=0001₂= 110x = 1310 13 10 = 110121101₂ = 0000₂ 010 The maximal value of x is 7 when a, b = 1010, 13₁0 and a, b = 1110, 1210- The output from the program should be 7. Here is the pseudocode for the algorithm which solves this problem, function max_xor (lower: unsigned int, upper: unsigned int) → unsigned int unsigned int a, b, max, x max - 0 for a lower to upper do for b - a to do x+a+b if x > max then max-x end for end for return max end function max_xor function main ( unsigned int lower, max, upper SysPrintStr ("Enter lower? ") lower SysReadInt() SysPrintStr ("Enter upper? ") upper - SysReadInt () max max_xor (lower, upper) SysPrintInt (max) SysExit ( end function main
Transcribed Image Text:2 Chapter 2 Exercise: Implementing Loops 1. You may use the source code template in h3.s found in the assignment zip archive as a starting point. Let lower and upper be two positive integers with 1 ≤ lower, upper ≤ 10³ and lower ≤ upper. Let a and b be two positive integers with lower ≤ a,b ≤ upper and a ≤ b. Let x =ab. For all pairs of a and b satisfying the specified conditions, find and print the maximal value of x. For example, suppose lower = 10₁0 and upper = 1310. The algorithm will compute x for each a, b pair where 1010 <a,b≤13₁0 anda<b, x = 1010 1010 1010₂1010₂=0000₂ 010x = 1010 01110101021011₂=0001₂= 110x= 1010 12 10 = 1010₂1100₂ = 0110₂=610x = 1010 1310 = 101021101₂-0111₂ = 710 X = 11101110 1011₂01011₂ - 0000₂= 010x = 11101210 = 1011₂2 1100₂ 0111₂= 710x = 1110 13 ₁0 = 1011₂1101₂= 0110₂= 6₁0x = 1210 1210 1100₂1100₂ = 0000₂=0₁0x=12101310 = 1100₂1101₂=0001₂= 110x = 1310 13 10 = 110121101₂ = 0000₂ 010 The maximal value of x is 7 when a, b = 1010, 13₁0 and a, b = 1110, 1210- The output from the program should be 7. Here is the pseudocode for the algorithm which solves this problem, function max_xor (lower: unsigned int, upper: unsigned int) → unsigned int unsigned int a, b, max, x max - 0 for a lower to upper do for b - a to do x+a+b if x > max then max-x end for end for return max end function max_xor function main ( unsigned int lower, max, upper SysPrintStr ("Enter lower? ") lower SysReadInt() SysPrintStr ("Enter upper? ") upper - SysReadInt () max max_xor (lower, upper) SysPrintInt (max) SysExit ( end function main
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