2) Battery lifetime is normally distributed for large samples. The mean lifetime is 500 daysand the standard deviation is 61 days.a) Find the distribution by filling in the blanks:X~N(b) Find the probability of batteries that have lifetimes longer than 561 days? Round to 4decimals.c) Find the probability of batteries that have lifetimes at most 497 days? Round to 4decimals.

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Answered: 2) Battery lifetime is normally…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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According to the latest internet usage survey of college students, the amount of time spent on social media per day is normally distributed with a mean equal to 210 minutes and a standard deviation of 45 minutes. Based on this survey, find the probability that the amount of time spent on social media by college students is between 150 and 300 minutes per day. Round answer to 4 decimal places.
The mean number of carats for 313 diamonds in a sample data set is 0.506 carats, with a standard deviation of 0.145 carats. Use the mean and standard deviation to form an interval that will contain at least 75% of the carat values in the data set. (Round your answer to 3 decimal places)
a standardize exam scores are normally distributed,in a recent year,the mean test scores was 1490,standard deviation was 320,the test sscores four for studentselected at a random are;1940,1249,and 1380.Find the Zscores that correspond to each vale and determine whether any of the values are unusual
to qualify for a police academy, applicants are given a test of physical fitness. The scores are normally distributed with a mean of 66 and a standard deviation of 10 . If only the top 13% of the applicants are selected, find the cutoff score. Round z-value calculations to 2 decimal places and the final answer up to the nearest whole number. Cutoff score
The Michelin tires in average will last for 60000 miles. A technician claims that the deviation of mileage for wearied off tires is 25000 miles. If 16 such tires are tested, find the probability that for those tires the average wearied off mileage is between 55000 and 65000 miles.
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P., the 58- percentile. This is the temperature reading separating the bottom 58% from the top 42%. P = °C Question Help: D Post to forum Submit Question Type here to search 耳
A standardized exam's scores are normally distributed. In a recent year, the mean test score was 1544 and the standard deviation was 314.The test scores of four students selected at random are 1940, 1290, 2250,and 1420.Find the z-scores that correspond to each value and determine whether any of the values are unusual. (Round to 2 decimal places as needed.)
The average number of cavities that thirty-year-old Americans have had in their lifetimes is 5. Do twenty year-olds have fewer cavities? The data show the results of a survey of 15 twenty-year-olds who were asked how many cavities they have had. Assume that the distribution of the population is normal. 3, 4, 4, 4, 5, 5, 6, 4, 5, 4, 3, 5, 6, 5, 3 What can be concluded at the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? v|| Select an answer H: ?v Select an answer v c. The test statistic ? (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton mean is significantly less than 5 at o =- 0.05, so there is sufficient evidence to conclude that the population mean number of cavities for…
Assume that blood pressure readings are normally distributed with μ= 124 and σ= 9. A researcher wishes to select people for a study but wants to exclude the top and bottom 9 percent. What would be the upper and lower readings to qualify people to participatein the study?

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