(2) Area of Triangle A=11* Of Triangle formed by V' and W in es =√6 A (11012) BC21014) ((|12₁k)| area = 1 AB = (2100) - (11012) = (1/₁10 (-1) 2 7 (0₁2, (²-2) ()- p AC =/ (112₁K) - (11012) = Area = 1/₂ 11ABXAC² || [ VE = ² пискунорнор 2√6 =V let X₁ = K X₂=-2K HỂ XÁC IT TË =- 0 1 -1 0 2 K-2 => [ (K-2)12) -ĴEO] HE COL kî So [ %/1] = K[ -=¹2₂] So eigen Vector 2 = -2 15 [12] 7 how
(2) Area of Triangle A=11* Of Triangle formed by V' and W in es =√6 A (11012) BC21014) ((|12₁k)| area = 1 AB = (2100) - (11012) = (1/₁10 (-1) 2 7 (0₁2, (²-2) ()- p AC =/ (112₁K) - (11012) = Area = 1/₂ 11ABXAC² || [ VE = ² пискунорнор 2√6 =V let X₁ = K X₂=-2K HỂ XÁC IT TË =- 0 1 -1 0 2 K-2 => [ (K-2)12) -ĴEO] HE COL kî So [ %/1] = K[ -=¹2₂] So eigen Vector 2 = -2 15 [12] 7 how
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Please explain in a sentence only the way of the answer, especially in the marked section. As well as the relationship with the question. Don't give solutions in other ways. Thank u chapter
![(2) Area of Triangle
A=11√ of Triangle formed by V' and W
A (11012) BC21014) ((|12₁k)| area = 1
AB = (20₁1) - (11012)
= (1/₁0(-1)
AC =/ (112₁K) - (11012)
Area = 1₂11 ABXAC² ||
пискунорнор
] VG =
2√6
in es
7
(0₁2, (²-2) (1) p
= V
let X₁ = K
X₂=-2K
HỂ XÁC
12 JE
لمكات
=- 0 1 -1
0 2 K-2
= 2^[ (K-2)+₂)
-ĴEO] HE COL
kî
So [ %/1] = K[ -=¹2₂]
in on
So eigen Vector 2 =-2 15
=-2 15 [12]
Row](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b0b5ef4-43f7-40b2-bb2e-4be47068e012%2F0ae04831-1cd7-43de-ab3a-5f671dc51aaa%2Fizv4esm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(2) Area of Triangle
A=11√ of Triangle formed by V' and W
A (11012) BC21014) ((|12₁k)| area = 1
AB = (20₁1) - (11012)
= (1/₁0(-1)
AC =/ (112₁K) - (11012)
Area = 1₂11 ABXAC² ||
пискунорнор
] VG =
2√6
in es
7
(0₁2, (²-2) (1) p
= V
let X₁ = K
X₂=-2K
HỂ XÁC
12 JE
لمكات
=- 0 1 -1
0 2 K-2
= 2^[ (K-2)+₂)
-ĴEO] HE COL
kî
So [ %/1] = K[ -=¹2₂]
in on
So eigen Vector 2 =-2 15
=-2 15 [12]
Row

Transcribed Image Text:7.
Let A=
2 2
2 -1
Find the characteristic polynomial. Find the eigenvalues.
Find an eigenvector for each eigenvalue. Find a matrix P?
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