2) A uniform electric field exists in the region between two oppositely charged parallel plates 1.54 cm apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval 1.53E[-6] s. S. 1 Ax = v¡t +5at² v = v¡ + at v² = v? + 2aAx a) Find the magnitude of the electric field. Answer: 137 b) Find the speed of the proton at the moment it strikes the negatively charged plate. Answer: 2.01E[4]

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2) A uniform electric field exists in the region between two oppositely charged parallel plates 1.54 cm apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval \(1.53 \times 10^{-6}\) s.

\[
\Delta x = v_i t + \frac{1}{2} a t^2
\]

\[
v = v_i + at
\]

\[
v^2 = v_i^2 + 2a \Delta x
\]

a) Find the magnitude of the electric field. **Answer: \(137 \, \text{N/C}\)**

b) Find the speed of the proton at the moment it strikes the negatively charged plate. **Answer: \(2.01 \times 10^4 \, \text{m/s}\)**
Transcribed Image Text:2) A uniform electric field exists in the region between two oppositely charged parallel plates 1.54 cm apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval \(1.53 \times 10^{-6}\) s. \[ \Delta x = v_i t + \frac{1}{2} a t^2 \] \[ v = v_i + at \] \[ v^2 = v_i^2 + 2a \Delta x \] a) Find the magnitude of the electric field. **Answer: \(137 \, \text{N/C}\)** b) Find the speed of the proton at the moment it strikes the negatively charged plate. **Answer: \(2.01 \times 10^4 \, \text{m/s}\)**
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