2) A uniform electric field exists in the region between two oppositely charged parallel plates 1.54 cm apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval 1.53E[-6] s. S. 1 Ax = v¡t +5at² v = v¡ + at v² = v? + 2aAx a) Find the magnitude of the electric field. Answer: 137 b) Find the speed of the proton at the moment it strikes the negatively charged plate. Answer: 2.01E[4]

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2) A uniform electric field exists in the region between two oppositely charged parallel plates 1.54 cm
apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface
of the opposite plate in a time interval 1.53E[-6] s.
Ax = v;t +5at²
.2
v = v; + at
v2 = v? + 2aAx
a) Find the magnitude of the electric field. Answer:137
N
C
b) Find the speed of the proton at the moment it strikes the negatively charged plate.
Answer:2.01E[4]"
m
S
Transcribed Image Text:2) A uniform electric field exists in the region between two oppositely charged parallel plates 1.54 cm apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval 1.53E[-6] s. Ax = v;t +5at² .2 v = v; + at v2 = v? + 2aAx a) Find the magnitude of the electric field. Answer:137 N C b) Find the speed of the proton at the moment it strikes the negatively charged plate. Answer:2.01E[4]" m S
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