**Problem 2**A stack of two crates is being lifted *upwards* by two cables, as shown in the figure below. The tension in each cable is 2270 N. You may assume that the masses of the cables are negligible compared to the masses of the crates. *Do not use Newton’s 3rd Law; use only Newton’s 2nd Law.***(a)** Using Newton’s 2nd Law, calculate the force that the top crate exerts on the bottom crate and the force that the bottom crate exerts on the top crate. *(answer: F_bottom-on-top = F_top-on-bottom = 3062 N)***(b)** The maximum tension that each cable can handle without breaking is 3230 N. Calculate the maximum upward acceleration that the load can have without breaking the cables. *(answer: 8.97 m/s²)***Diagram Explanation:**- The diagram displays two rectangular crates stacked vertically. - The top crate is labeled as *232 kg* and the bottom crate as *112 kg*.- Two cables are shown lifting the crates upwards, with arrows pointing in the upward direction, indicating the tension in the cables.

Answered: Image /qna-images/answer/2270446b-d211-431d-ba9c-b4396de47b82.jpg

(2) A stack of two crates is being lifted upwards by two cables, as shown in the figure below. The tension in each cable is 2270 N. You may assume that the masses of the cables are negligible compared to the masses of the crates. Do not use Newton's 3rd Law; use only Newton's 2nd Law. (a) Using Newton's 2nd Law, calculate the force that the top crate exerts on the bottom crate and the force that the bottom crate exerts on the top crate. (answer: Fotom on-top = Fiop-on-bottom= 3062 N) (b) The maximum tension that each cable can handle without breaking is 3230 N. Calculate the maximum upward acceleration that the load can have without breaking the cables. (answer: 8.97 m/s²) 232 kg 112 kg

(2) A stack of two crates is being lifted upwards by two cables, as shown in the figure below. The tension in each cable is 2270 N. You may assume that the masses of the cables are negligible compared to the masses of the crates. Do not use Newton's 3rd Law; use only Newton's 2nd Law. (a) Using Newton's 2nd Law, calculate the force that the top crate exerts on the bottom crate and the force that the bottom crate exerts on the top crate. (answer: Fotom on-top = Fiop-on-bottom= 3062 N) (b) The maximum tension that each cable can handle without breaking is 3230 N. Calculate the maximum upward acceleration that the load can have without breaking the cables. (answer: 8.97 m/s²) 232 kg 112 kg

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: 3) Two masses MA 2.0 kg and mB 5.0 kg are on inclines and are connected together by a string as…

Q: Two boxes sit side-by-side on a smooth horizontal surface. The lighter box has a mass of 5.2 kg; the…

Q: Friction force is inversely proportional to the magnitude of the normal force exerted on an object…

A: Given Friction force is inversely proportional to the magnitude of the normal force exerted on an…

Q: A lumberjack is trying to drag a small tree that he cut down. If the static coefficient of friction…

A: SOlution: given that trees weight W = 430 N coef of friction = 0.5

Q: Two persons are pulling the ends of a string in such a way that the string is stretched…

A: The persons cannot make it horizontal again by pulling it with a greater force because the vertical…

Q: A 315-pound box is placed on a ramp that is inclined 22.6°. (a) Find the magnitude of the force…

Q: You hold one end of a rope and pull horizontally with a force of 65 N. Calculate the tension in the…

Q: 21. A canal barge is being pulled along a canal by two horses, one on either side of the canal. One…

Q: wo blocks are positioned on surfaces, each inclined at the same angle of 41.9 degrees with respect…

A: Given:- The mass mb = 3.95 kg angle θ= 41.9° the coefficient of kinetic friction for both blocks…

Q: Two blocks are in contact on a frictionless table. A horizontal force is applied to one block, as…

Q: A man standing on the ground exerts a horizontal force of 461 N when pushing on his friend standing…

A: Given that: F=461 NMm=70 kgMs=2 kgμs=0.84

Q: A box rest on an incline making a 35 angle with the horizontal. It is found that a parallel force…

A: Given data The angle of inclination of the incline is θ=35°. The parallel force applied to the block…

Q: You are trying to lift a stack of books off the table. The stack of books has a mass of 15 kg. What…

Q: The figure below shows a block with mass m = 5.1 kg pulled up a surface inclined at an angle of ? =…

Q: A 70 kg high jumper is attempting to clear a bar at a height of 2 meters. The coefficient of…

A: Given that:M=70 kgFnet,y=400 Nμ=0.35

A: Given: Coefficient of friction between A & B is μAB = 0.3 Coefficient of friction between B…

Q: A 1000-kg load is being moved by a crane. Find the tension in the cable that supports the load as (a…

A: Given,Mass of load, m=1000 kg

Q: (3) A stack of two crates is being lifted upwards by two cables, as shown in the figure below. The…

A: Solution:Given:T1 = tension in each cable = 2270 Nm1 = mass of top crate = 232 kgm2 = mass of bottom…

Q: A wooden block weighing 9 N is at rest on top of a wooden desk. The coefficient of static friction…

A: Given data: Weight of the block (W) = mg = 9 NCoefficient of kinetic friction (μk) = 0.56

Q: A small block of mass m rests on the rough, sloping side of a triangular block of mass M which…

Q: 49. (II) Two crates, of mass 65 kg and 125 kg, are in contact and at rest on a horizontal surface…

Q: Suppose you have a 120-kg wooden crate resting on a w por. (a) What maximum force can you exert…

Q: 5. (a) The weight of the block in the diagram is 54 N. The coefficient of static friction between…

A: 5. (a) Given:The weight of the block (W) = 54 Ncoefficient of static friction between the block and…

Question

**Problem 2**

A stack of two crates is being lifted *upwards* by two cables, as shown in the figure below. The tension in each cable is 2270 N. You may assume that the masses of the cables are negligible compared to the masses of the crates. *Do not use Newton’s 3rd Law; use only Newton’s 2nd Law.*

**(a)** Using Newton’s 2nd Law, calculate the force that the top crate exerts on the bottom crate and the force that the bottom crate exerts on the top crate.
*(answer: F_bottom-on-top = F_top-on-bottom = 3062 N)*

**(b)** The maximum tension that each cable can handle without breaking is 3230 N. Calculate the maximum upward acceleration that the load can have without breaking the cables.
*(answer: 8.97 m/s²)*

**Diagram Explanation:**

- The diagram displays two rectangular crates stacked vertically.
- The top crate is labeled as *232 kg* and the bottom crate as *112 kg*.
- Two cables are shown lifting the crates upwards, with arrows pointing in the upward direction, indicating the tension in the cables.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Similar questions

Block A has a mass of 3.00 kg and block B has a mass of 8.00kg. The two blocks are stacked on the ramp with an incline of angle = 30 degrees. Determine the largest horizontal force F that can be applied to block B
A 50-kg traffic light is suspended from two wires making angles of 1=53, and 2 = 37 with thehorizontal axis. Find the tension T1 and T2 on the wires. Note that the values are given to two significantfigures.
The glue on a piece of tape can exert forces. Can these forces be a type of simple friction? Explain, considering especially that tape can stick to vertical walls and even to ceilings.
Two ropes apply a force to a boat. The first is 200 N in the positive x direction, and the second is 250 N in the positive y direction. At what angle must a third rope tension be applied in order to keep the boat at rest? Your Answer:
An elevator is supported by a cable and moving downward through the elevator shaft at a constant speed. How does the upward tension force compare to the downward force of gravity? O The upward tension force is stronger than the downward force of gravity. The downward force of gravity is stronger than the upward tension force. The tension force and the force of gravity are of equal strength.
An elevator cab that weighs 28.6 kN moves upward. What is the tension in the cable if the cab's speed is (a) increasing at a rate of 1.20 m/s? and (b) decreasing at a rate of 1.20 m/s?? (a) Number i Units (b) Number i Units This answer has no units • (degrees) Attempts: 0 of 3 used Submit Answer Save for Later kg m/s m/s^2 N N/m kg-m/s or N.s N/m^2 or Pa kg/m^3 m/s^3 times
You are standing in an elevator that is accelerating upward. The magnitude of the force that you exert on the elevator (a) is larger than the magnitude of the force that the elevator exerts on you (b) is smaller than the magnitude of the force that the elevator exerts on you (c) is equal to the force magnitude of the that the elevator exerts on you (d) none of the above
A contestant in a winter sporting event pushes a 27 kg block of ice across a frozen lake as shown below. The angle between the applied force F and the horizontal is 23 degrees. The coefficient of static friction between the ice and the frozen lake is 0.06. Calculate the minimum force F he must exert to get the block moving.
What is the magnitude of the static friction force required to keep a 2.00 kg block resting on an inclined plane at an angle 25 degrees? If the angle was increased, such that the incline plane was steeper, would the magnitude of the static friction force required to hold the block at rest increase, decrease, or stay the same?
7)A desk with a mass of 75.0 kg sits on a floor, and the coefficient of static friction between the two surfaces is 0.40. Draw a force diagram for the problem and how much force must someone apply in a direction horizontal to the surface of the floor to get the desk moving?