#2 A load consists of a 60-2 resistor in parallel with a 90-uF capacitor. If the load is connected to a voltage source vs(t) = 160 cos 2000t, find the average power delivered to the load. #3.Assuming that vs = 8 cos(2t -40°) V in the circuit of Fig 1 find the average power delivered to Solution #2 20 F4 F5 160Z0 R C 1 1 90 μF =-j5.5556 j@C j90x10x2x103 I=160/Z_par = 2.6667 + 28.8000j Here Z_par (R*Zc)/(R+Zc), where Zc= -j/wC So I abs 28.923 A and phase angle phi = 84.71 degrees So Pavg for resistor = 0.5 * (I_abs)^2*R* Cos(84.71)= 2313.9 W < de 69 8 < DII F6 F7 F8 F9
#2 A load consists of a 60-2 resistor in parallel with a 90-uF capacitor. If the load is connected to a voltage source vs(t) = 160 cos 2000t, find the average power delivered to the load. #3.Assuming that vs = 8 cos(2t -40°) V in the circuit of Fig 1 find the average power delivered to Solution #2 20 F4 F5 160Z0 R C 1 1 90 μF =-j5.5556 j@C j90x10x2x103 I=160/Z_par = 2.6667 + 28.8000j Here Z_par (R*Zc)/(R+Zc), where Zc= -j/wC So I abs 28.923 A and phase angle phi = 84.71 degrees So Pavg for resistor = 0.5 * (I_abs)^2*R* Cos(84.71)= 2313.9 W < de 69 8 < DII F6 F7 F8 F9
Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Power and the average power.
#2 A load consists of a 60-2 resistor in parallel with a 90-uF capacitor. If the load is connected to a
voltage source vs(t) = 160 cos 2000t, find the average power delivered to the load.
I need to show all work please
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