2) A Given: Rectancle ABCD 2BDC=2x-4U t ZBDA=30 la) Copy d label l6) solve for x () what property, allows to set up J solve for ou 3と

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.3: Hyperbolas
Problem 44E
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### Geometry Problem: Understanding Rectangles and Properties of Angles

#### Given:
- **Rectangle ABCD**
- \(\angle BDC = 2x - 40\)
- \(\angle BDA = 30\)

#### Tasks:
1. **Copy and Label** the diagram.
2. **Solve for \(x\)**.
3. **What property allows you to set up and solve for \(x\)?**

#### Diagram:
The diagram represents a rectangle \(ABCD\) with diagonals \(AC\) and \(BD\) intersecting at point \(E\). Each corner of the rectangle (\(A\), \(B\), \(C\), \(D\)) and the intersection point \(E\) is labeled accordingly.

---

To solve the problem:

1. **Copy and Label**:
   - Draw a rectangle and name the vertices \(A\), \(B\), \(C\), and \(D\) in a clockwise or counterclockwise order.
   - Draw the diagonals \(AC\) and \(BD\) intersecting at point \(E\).
   - Label angles \(\angle BDC\) and \(\angle BDA\) as given: \(\angle BDC = 2x - 40\) and \(\angle BDA = 30\).

2. **Solve for \(x\)**:
   - According to the property of rectangles, diagonals bisect each other. Hence, \(\angle BDA = \angle BDC\).
   - Set the expressions equal to each other: \(2x - 40 = 30\).
   - Solve the equation:
     \[
     2x - 40 = 30
     \]
     \[
     2x = 70
     \]
     \[
     x = 35
     \]

3. **Property Used**:
   - The property used here is the fact that in a rectangle, the diagonals are congruent and bisect each other. This makes the angles formed by these diagonals congruent.

By following these steps, you can understand how to label diagrams correctly, set up and solve equations based on geometric properties, and apply these concepts to solve for unknown variables.
Transcribed Image Text:### Geometry Problem: Understanding Rectangles and Properties of Angles #### Given: - **Rectangle ABCD** - \(\angle BDC = 2x - 40\) - \(\angle BDA = 30\) #### Tasks: 1. **Copy and Label** the diagram. 2. **Solve for \(x\)**. 3. **What property allows you to set up and solve for \(x\)?** #### Diagram: The diagram represents a rectangle \(ABCD\) with diagonals \(AC\) and \(BD\) intersecting at point \(E\). Each corner of the rectangle (\(A\), \(B\), \(C\), \(D\)) and the intersection point \(E\) is labeled accordingly. --- To solve the problem: 1. **Copy and Label**: - Draw a rectangle and name the vertices \(A\), \(B\), \(C\), and \(D\) in a clockwise or counterclockwise order. - Draw the diagonals \(AC\) and \(BD\) intersecting at point \(E\). - Label angles \(\angle BDC\) and \(\angle BDA\) as given: \(\angle BDC = 2x - 40\) and \(\angle BDA = 30\). 2. **Solve for \(x\)**: - According to the property of rectangles, diagonals bisect each other. Hence, \(\angle BDA = \angle BDC\). - Set the expressions equal to each other: \(2x - 40 = 30\). - Solve the equation: \[ 2x - 40 = 30 \] \[ 2x = 70 \] \[ x = 35 \] 3. **Property Used**: - The property used here is the fact that in a rectangle, the diagonals are congruent and bisect each other. This makes the angles formed by these diagonals congruent. By following these steps, you can understand how to label diagrams correctly, set up and solve equations based on geometric properties, and apply these concepts to solve for unknown variables.
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