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2 A co-current (same direction) heat exchanger has one line with 5 kg/s of n-butane at 120°C and 5 bar entering. The other line is cooling water entering at 20°C and 1 bar. The heat exchanger is long enough so that the two flows exit at the same temperature of 80°C. Calculate: a. The flow rate of cooling water needed, in kg/s. b. The process efficiency of the heat exchanger.

2 A co-current (same direction) heat exchanger has one line with 5 kg/s of n-butane at 120°C and 5 bar entering. The other line is cooling water entering at 20°C and 1 bar. The heat exchanger is long enough so that the two flows exit at the same temperature of 80°C. Calculate: a. The flow rate of cooling water needed, in kg/s. b. The process efficiency of the heat exchanger.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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2 A co-current (same direction) heat exchanger has one line with 5 kg/s of n-butane at 120°C and 5 bar entering. The other line is cooling water entering at 20°C and 1 bar. The heat exchanger is long enough so that the two flows exit at the same temperature of 80°C. Calculate: The flow rate of cooling water needed, in kg/s. b. The process efficiency of the heat exchanger. а.
Transcribed Image Text:2 A co-current (same direction) heat exchanger has one line with 5 kg/s of n-butane at 120°C and 5 bar entering. The other line is cooling water entering at 20°C and 1 bar. The heat exchanger is long enough so that the two flows exit at the same temperature of 80°C. Calculate: The flow rate of cooling water needed, in kg/s. b. The process efficiency of the heat exchanger. а.
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