(교)2 + a (7) + aT = T (피)3 + (a-1)교 =0 F{(7) + (a – 1)} = 0 e equilibrium points are 0 and t/1- a. ||

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question

Explain the determine purple and inf is here and Why did we choose this equilibrium point?

Proposition [22] Assume that p,q € R. Then
\p| + |q] < 1
is a sufficient condition for the asymptotic stability of the difference equation
Хn+1 — рап — qxn-1 — 0, п 3 0, 1,... .
Lemma 1. The equilibrium points of the difference equation (2) are 0 and ±/1- a
Proof.
(x)
+ a
(7)° + ax = X
(7) + (a – 1) = 0
7{(T) + (a – 1)} = 0
This means that the equilibrium points are 0 and ±/1 – a.
Transcribed Image Text:Proposition [22] Assume that p,q € R. Then \p| + |q] < 1 is a sufficient condition for the asymptotic stability of the difference equation Хn+1 — рап — qxn-1 — 0, п 3 0, 1,... . Lemma 1. The equilibrium points of the difference equation (2) are 0 and ±/1- a Proof. (x) + a (7)° + ax = X (7) + (a – 1) = 0 7{(T) + (a – 1)} = 0 This means that the equilibrium points are 0 and ±/1 – a.
Motivated by the above studies, we study the dynamics of following higher
order difference equation
Xn+1
A + B
(2)
п-т
where A, B are positive real numbers and the initial conditions are positive
numbers. Additionally, we investigate the boundedness, periodicity, oscillation
behaviours, global asymptotically stability and rate of convergence of related
higher order difference equations.
Transcribed Image Text:Motivated by the above studies, we study the dynamics of following higher order difference equation Xn+1 A + B (2) п-т where A, B are positive real numbers and the initial conditions are positive numbers. Additionally, we investigate the boundedness, periodicity, oscillation behaviours, global asymptotically stability and rate of convergence of related higher order difference equations.
Expert Solution
Step 1

Here,

x=xx2+αxx2+α=xxx2+α-x=0xx2+α-1=0x=0, x2+α-1=0x=0, x2=1-αx=0, x=±1-α

The solution of the equation is: x=0,±1-α

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