2) A 400-N block is dragged along a horizontal surface by an applied force F as shown. The coefficient of kinetic friction is uk = 0.4 and the block moves at constant velocity. The magnitude of F is:

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

A 400-N block is dragged along a horizontal surface by an applied force \( \vec{F} \) as shown in the diagram. The coefficient of kinetic friction is \( \mu_k = 0.4 \) and the block moves at constant velocity. The magnitude of \( \vec{F} \) is:

A) 100 N  
B) 150 N  
C) 200 N  
D) 290 N  
E) 400 N  

**Diagram Explanation:**

- The diagram shows a block on a horizontal surface.
- An applied force \( \vec{F} \) is acting on the block at an angle.
- The force \( \vec{F} \) is decomposed into two components:
  - The vertical component is \( \frac{3}{5}F \).
  - The horizontal component is \( \frac{4}{5}F \).

**Notes:**

- Since the block moves at a constant velocity, the net force on it is zero.
- This means the horizontal component of the applied force must balance out the frictional force.
Transcribed Image Text:**Problem Statement:** A 400-N block is dragged along a horizontal surface by an applied force \( \vec{F} \) as shown in the diagram. The coefficient of kinetic friction is \( \mu_k = 0.4 \) and the block moves at constant velocity. The magnitude of \( \vec{F} \) is: A) 100 N B) 150 N C) 200 N D) 290 N E) 400 N **Diagram Explanation:** - The diagram shows a block on a horizontal surface. - An applied force \( \vec{F} \) is acting on the block at an angle. - The force \( \vec{F} \) is decomposed into two components: - The vertical component is \( \frac{3}{5}F \). - The horizontal component is \( \frac{4}{5}F \). **Notes:** - Since the block moves at a constant velocity, the net force on it is zero. - This means the horizontal component of the applied force must balance out the frictional force.
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