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2) 6.20 The current shown in Fig. P6.20 is applied to a 250 nF capacitor. The initial voltage on the capacitor is zero, the fol- a) Find the charge on the capacitor at t = b) Find the voltage on the capacitor at t = c) How much energy is stored in the capacitor by PSPICE 30 us. MULTISIM olt- 50 us. er- this current? Figure P6.20 i (mA) 400 05 10 (us) 30 40 50 -300

2) 6.20 The current shown in Fig. P6.20 is applied to a 250 nF capacitor. The initial voltage on the capacitor is zero, the fol- a) Find the charge on the capacitor at t = b) Find the voltage on the capacitor at t = c) How much energy is stored in the capacitor by PSPICE 30 us. MULTISIM olt- 50 us. er- this current? Figure P6.20 i (mA) 400 05 10 (us) 30 40 50 -300

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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6.20. Please do by hand and not through pspice
**6.20** The current shown in Fig. P6.20 is applied to a 250 nF capacitor. The initial voltage on the capacitor is zero. a) Find the change on the capacitor at \( t = 30 \) μs. b) Find the voltage on the capacitor at \( t = 50 \) μs. c) How much energy is stored in the capacitor by this current? **Figure P6.20 Explanation:** - The graph illustrates a current pulse over time. - The x-axis represents time (\( \mu s \)), marked from 0 to 50 μs. - The y-axis represents current (mA), ranging from -300 to 400 mA. - At \( t = 0 \), the current is at 0 mA. - The current quickly rises to 400 mA by \( t = 5 \) μs. - It holds steady at 400 mA until \( t = 10 \) μs, after which it drops to 0 by \( t = 20 \) μs. - The current then descends sharply to -300 mA at \( t = 30 \) μs, maintaining this level until \( t = 40 \) μs, before returning to 0 by \( t = 50 \) μs. **6.21** The rectangular-shaped current pulse shown in Fig. P6.21 is applied to a 5 μF capacitor. The initial voltage on the capacitor is a 12V drop in the reference direction of the current. Derive the expression for the capacitor voltage for the time... (text cut off)
Transcribed Image Text:**6.20** The current shown in Fig. P6.20 is applied to a 250 nF capacitor. The initial voltage on the capacitor is zero. a) Find the change on the capacitor at \( t = 30 \) μs. b) Find the voltage on the capacitor at \( t = 50 \) μs. c) How much energy is stored in the capacitor by this current? **Figure P6.20 Explanation:** - The graph illustrates a current pulse over time. - The x-axis represents time (\( \mu s \)), marked from 0 to 50 μs. - The y-axis represents current (mA), ranging from -300 to 400 mA. - At \( t = 0 \), the current is at 0 mA. - The current quickly rises to 400 mA by \( t = 5 \) μs. - It holds steady at 400 mA until \( t = 10 \) μs, after which it drops to 0 by \( t = 20 \) μs. - The current then descends sharply to -300 mA at \( t = 30 \) μs, maintaining this level until \( t = 40 \) μs, before returning to 0 by \( t = 50 \) μs. **6.21** The rectangular-shaped current pulse shown in Fig. P6.21 is applied to a 5 μF capacitor. The initial voltage on the capacitor is a 12V drop in the reference direction of the current. Derive the expression for the capacitor voltage for the time... (text cut off)
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