2 4 2 [²√² (1 – xy²) dady − -1 0

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Compute the attached double integral as a limmit of Riemann sums. (Hint: Use the two provided sums)

### Double Integral Explanation

This image shows a double integral, which is used to calculate the volume under a surface in a given region in the xy-plane.

The expression is:

\[
\int_{-1}^{2} \int_{0}^{4} (1 - xy^2) \, dx \, dy
\]

#### Explanation:

1. **Integrals**:
   - The outer integral \(\int_{-1}^{2}\) indicates integration with respect to \(y\), from \(y = -1\) to \(y = 2\).
   - The inner integral \(\int_{0}^{4}\) indicates integration with respect to \(x\), from \(x = 0\) to \(x = 4\).

2. **Function**: 
   - The integrand is \(1 - xy^2\), which is the function we integrate over the specified region. It represents the height of the surface above each point \((x, y)\).

3. **Calculation Process**:
   - First, integrate \(1 - xy^2\) with respect to \(x\) from 0 to 4 while keeping \(y\) constant.
   - Then, integrate the result with respect to \(y\) from -1 to 2.

This process will give the total volume under the surface defined by \(1 - xy^2\) and above the region in the xy-plane specified by the bounds \([-1, 2]\) for \(y\) and \([0, 4]\) for \(x\).
Transcribed Image Text:### Double Integral Explanation This image shows a double integral, which is used to calculate the volume under a surface in a given region in the xy-plane. The expression is: \[ \int_{-1}^{2} \int_{0}^{4} (1 - xy^2) \, dx \, dy \] #### Explanation: 1. **Integrals**: - The outer integral \(\int_{-1}^{2}\) indicates integration with respect to \(y\), from \(y = -1\) to \(y = 2\). - The inner integral \(\int_{0}^{4}\) indicates integration with respect to \(x\), from \(x = 0\) to \(x = 4\). 2. **Function**: - The integrand is \(1 - xy^2\), which is the function we integrate over the specified region. It represents the height of the surface above each point \((x, y)\). 3. **Calculation Process**: - First, integrate \(1 - xy^2\) with respect to \(x\) from 0 to 4 while keeping \(y\) constant. - Then, integrate the result with respect to \(y\) from -1 to 2. This process will give the total volume under the surface defined by \(1 - xy^2\) and above the region in the xy-plane specified by the bounds \([-1, 2]\) for \(y\) and \([0, 4]\) for \(x\).
The image contains two mathematical formulas related to summations.

1. **Sum of the first n natural numbers:**

   \[
   \sum_{j=1}^{n} j = \frac{1}{2} n (n + 1)
   \]

   This formula represents the sum of the integers from 1 to \( n \). It states that the sum can be calculated using the expression \(\frac{1}{2} n (n + 1)\).

2. **Sum of the squares of the first n natural numbers:**

   \[
   \sum_{j=1}^{n} j^2 = \frac{1}{6} n (n + 1) (2n + 1)
   \]

   This formula provides the sum of the squares of integers from 1 to \( n \). The formula used here is \(\frac{1}{6} n (n + 1) (2n + 1)\).

These formulas are often used in mathematical analysis and proofs, especially in topics related to arithmetic series and quadratic sums.
Transcribed Image Text:The image contains two mathematical formulas related to summations. 1. **Sum of the first n natural numbers:** \[ \sum_{j=1}^{n} j = \frac{1}{2} n (n + 1) \] This formula represents the sum of the integers from 1 to \( n \). It states that the sum can be calculated using the expression \(\frac{1}{2} n (n + 1)\). 2. **Sum of the squares of the first n natural numbers:** \[ \sum_{j=1}^{n} j^2 = \frac{1}{6} n (n + 1) (2n + 1) \] This formula provides the sum of the squares of integers from 1 to \( n \). The formula used here is \(\frac{1}{6} n (n + 1) (2n + 1)\). These formulas are often used in mathematical analysis and proofs, especially in topics related to arithmetic series and quadratic sums.
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