Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Please answer question #2 with details on how to do it.
Make handwriting legible please when writing out x,y,z etc. Thank you.

Transcribed Image Text:### Linear Algebra: Suggested Exercises Using Determinants and the Cayley-Hamilton Theorem
#### Exercise 1
Suppose \( G = \begin{pmatrix}
-2 & 1 & 5 \\
0 & x & -4 \\
-4 & 2 & x + 4
\end{pmatrix} \). Determine the values of \( x \) for which \( \text{det}(G) = 0 \).
#### Exercise 2
Suppose that \( Z = \begin{pmatrix}
0 & 15 & 0 \\
2 & 4 & 0 \\
3 & 6 & 6
\end{pmatrix} \). Given that the characteristic polynomial of this matrix is \( P(\lambda) = \lambda^3 - 20\lambda^2 + 94\lambda - 60 \), use the Cayley-Hamilton theorem to find \( Z^{-1} \).
#### Exercise 3
Suppose that \( K = \begin{pmatrix}
2 & -1 \\
0 & 5
\end{pmatrix} \). Use the Cayley-Hamilton theorem to find \( K^3 \).
### Explanation of Key Concepts:
1. **Determinant (det)**:
- The determinant is a scalar value that is computed from the elements of a square matrix.
- It is used in a variety of matrix-related problems, including determining whether a matrix is invertible.
2. **Characteristic Polynomial**:
- The characteristic polynomial of a matrix is obtained by computing the determinant of \(\lambda I - A\), where \(I\) is the identity matrix and \(A\) is the given matrix.
- It is denoted as \( P(\lambda) \) and is used in the Cayley-Hamilton theorem.
3. **Cayley-Hamilton Theorem**:
- This theorem states that every square matrix over a commutative ring (like real or complex numbers) satisfies its own characteristic polynomial.
- For a matrix \( A \) with characteristic polynomial \( P(\lambda) = \lambda^n + c_{n-1}\lambda^{n-1} + \cdots + c_1 \lambda + c_0 \), the theorem asserts that \( P(A) = A^n + c_{n-1}A^{n-1} + \cdots
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