2 1. pH Buffers are solutions that contain mixtures at similar concentrations of a weak acid and its conjugate base. Below are conjugate acid-base pairs that can be used to make pH buffers in this lab. For each pair, label the weak acid and the conjugate base. buffer 1: NH3 buffer 2: buffer 3: CH3COOH HPO4²- Name: NHA CH3COO H₂PO4

2 1. pH Buffers are solutions that contain mixtures at similar concentrations of a weak acid and its conjugate base. Below are conjugate acid-base pairs that can be used to make pH buffers in this lab. For each pair, label the weak acid and the conjugate base. buffer 1: NH3 buffer 2: buffer 3: CH3COOH HPO4²- Name: NHA CH3COO H₂PO4

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Determine the concentration of CH NH¸* in a buffer solution by constructing an ICE table, writing the equilibrium constant expression, and use this information to determine the concentration of CH NH+. The Kb for CH NH₂ is 3.8 × 10-10. Complete Parts 1-3 before submitting your answer. 2 1 2 3 NEXT > 2 A buffer solution contains dissolved CH NH and CH NH Cl. The initial concentration of CH NH2 is 0.50 M. The pH at equilibrium of the buffer is 4.20. Let x represent the original concentration of CH NH+ in the water. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) CH NH2(aq) + H₂O(I) = OH(aq) + C HẠNH, (aq) RESET 0 0.50 x 4.20 -4.20 6.3 x 10-5 -6.3 x 10-5 1.6 × 10-10 -1.6 × 10-10 3.8 × 10-10 -3.8 × 10-10 x +4.20 x-4.20 x + 6.3 x 10-5 x - 6.3 × 10-5 x + 1.6 × 10-10 x-1.6 × 10-10 x + 3.8 × 10-10 x - 3.8 × 10-10
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Exactly 100mL of 0.1M HF is titrated with 40 mL of 0.1M calcium hydroxide solution. Calculate the pH of this solution after the titration. HF Ka = 1.6 x 10-5 You must type the answer in the text box below. (You must show all your work on paper to get credit) Edit Format Table
1. all the aqueous solutions that are good buffer systems 2. a buffer solution is 0.421 m in hcn and 0.281 m in kcn, if Ka for Hcn is 4.0 * 10^-10. what is the PH of this buffer solution. b. a buffer solution is 0.495 m in h2s and 0.354 m in khs, if Ka1 for H2s is 1.0 * 10^-7. what is the PH of this buffer solution. c. a buffer solution is 0.455 m in NaHSO and 0.299 m in Na2SO3, if Ka for HSO3 is 6.4 * 10^-8. what is the PH of this buffer solution. 3. A 28.9 ml sample of a 0.385 m aqueous hydrocyanic acid solution is titrated with a 0.372 m aqueous sodium hydroxide solution. what is the ph at the start of the titration, before any sodium hydroxide has been added. b. A 31.9 ml sample of a 0.599 m aqueous hydrofluoric acid solution is titrated with a 0.242 m aqueous barium hydroxide solution. what is the ph after 15.8ml of base has been added. c. when a 23.8 ml sample of a 0.357 m aqueous acetic acid solution is titrated with a 0.459 m aqueous barium hydroxide solution. what is the ph…
Buffer is 200 ml of 0.15 M Tris-HCl buffer with a pH of 8.9 Write out the chemical equation for this buffer. Identify which species is the conjugate acid and conjugate base. What is Pka of this equilibrium? Calculate the ratio of the base to acid using the Henderson-Hasselbach equation.
for pH titration lab! please help
Which is true about buffer solutions? -they hold the pH close to the pKa -they contain comparable moles of a weak acid and a strong base - they hold pH constant at pH=7 -they prevent acids and bases from reaching equilibrium -they hold the pH close to the equivalence point pH
Calculate the pH after 0.032 mole of NaOH is added to 1.00 L of each of the following solutions. a. 0.145 M HONH, (K = 1.1 × 10-) pH = b. 0.145 M HONH, Cl pH = c. pure H₂O pH = d. a mixture containing 0.145 M HONH₂ and 0.145 M HỌNH3 C1 pH =
Determine the resulting pH when 0.040 mol of solid NaOH is added to a 200.0 mL buffer containing 0.100 mol C6H5NH3CI and 0.500 M C6H5NH2. The value of Kb for C6H5NH2 is 4.3 x 101°. 1 2 3 4 NEXT Use the table below to determine the moles of reactant and product after the reaction of the acid and base. You can ignore the amount of liquid water in the reaction. C6H;NH3*(aq) Он (aq) H20(1) C6H;NH2(aq) + + Before (mol) Change (mol) After (mol) 5 RESET 0.040 -0.040 0.500 -0.500 0.100 -0.100 +x 0.040 + x 0.040 - x 0.100 + x 0.100 - x 0.060 -0.060 -x 0.140 -0.140 0.020 -0.020
Solve correctly please , need both subparts to be solve.