2 - 1 Fit a cubic trend function to the data (- 2,11), (- 1,13), (0,13), (1,12), (2,11). Let po(t) = 1, p, (t) = t and p, (t) = t2 - 2. The orthogonal cubic polynomial is pa (t) =t3 -t. The vectors for Po: Pi, and p2 are 1 and -2 respectivel 1 - 1 2

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Q: =₁³-171. The vectors for Po. P₁, and p2 are 1 1 Fit a cubic trend function to the data (-2,6).…

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