1)The figure below shows two blocks with externalforces acting on the side of each block. a) Find the (common) acceleration of the blocks? b) What isthe net force on the larger block? c) What is the net force on the smaller block?

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1)The figure below shows two blocks with externalforces acting on the side of each block.

a) Find the (common) acceleration of the blocks?

b) What isthe net force on the larger block?

c) What is the net force on the smaller block?

d) What is the force that the larger block exerts on the smaller block?

e) What is the force that the smaller block exerts on the larger block?

**Analyzing Forces on Two Blocks**

This diagram represents two blocks on a horizontal surface, subject to various forces. Understanding the forces acting on the blocks is essential for comprehending basic mechanics principles.

**Diagram Explanation:**
1. **Blocks:**
   - There are two blocks depicted in the diagram.
     - The left block has a mass of \(1 \text{kg}\) (denoted by the label "1 kg").
     - The right block has a mass of \(3 \text{kg}\) (denoted by the label "3 kg").
   
2. **Forces Acting on the Blocks:**
   - There are forces acting horizontally on each block:
     - A force of \(5 \text{N}\) (5 Newtons) is applied to the left block (1 kg block) towards the right.
     - A force of \(3 \text{N}\) (3 Newtons) is applied to the right block (3 kg block) towards the left.

**Analyzing the System:**
- The two forces acting on the blocks are equal in magnitude but opposite in direction. However, they act on different objects, meaning they will affect the motion of those objects in different ways.

**Calculating the Net Force and Acceleration:**

1. **Net Force on Each Block:**
   - For the 1 kg block: The net force can be calculated as the applied force minus the reaction force from the 3 kg block.
     \[ F_{\text{net, 1kg}} = 5\text{N} - F_{\text{reaction}} \]
   - For the 3 kg block: It may be subject to additional forces depending on the interaction between it and the 1 kg block.
     \[ F_{\text{net, 3kg}} = F_{\text{reaction}} - 3\text{N} \]

2. **System as a Whole:**
   - To find the acceleration of the whole system, sum the forces acting on both blocks and divide by the total mass.
   \[ F_{\text{net, total}} = 5\text{N} - 3\text{N} = 2\text{N} \]
   \[ \text{Total mass} = 1\text{kg} + 3\text{kg} = 4\text{kg} \]
   - Using Newton's
Transcribed Image Text:**Analyzing Forces on Two Blocks** This diagram represents two blocks on a horizontal surface, subject to various forces. Understanding the forces acting on the blocks is essential for comprehending basic mechanics principles. **Diagram Explanation:** 1. **Blocks:** - There are two blocks depicted in the diagram. - The left block has a mass of \(1 \text{kg}\) (denoted by the label "1 kg"). - The right block has a mass of \(3 \text{kg}\) (denoted by the label "3 kg"). 2. **Forces Acting on the Blocks:** - There are forces acting horizontally on each block: - A force of \(5 \text{N}\) (5 Newtons) is applied to the left block (1 kg block) towards the right. - A force of \(3 \text{N}\) (3 Newtons) is applied to the right block (3 kg block) towards the left. **Analyzing the System:** - The two forces acting on the blocks are equal in magnitude but opposite in direction. However, they act on different objects, meaning they will affect the motion of those objects in different ways. **Calculating the Net Force and Acceleration:** 1. **Net Force on Each Block:** - For the 1 kg block: The net force can be calculated as the applied force minus the reaction force from the 3 kg block. \[ F_{\text{net, 1kg}} = 5\text{N} - F_{\text{reaction}} \] - For the 3 kg block: It may be subject to additional forces depending on the interaction between it and the 1 kg block. \[ F_{\text{net, 3kg}} = F_{\text{reaction}} - 3\text{N} \] 2. **System as a Whole:** - To find the acceleration of the whole system, sum the forces acting on both blocks and divide by the total mass. \[ F_{\text{net, total}} = 5\text{N} - 3\text{N} = 2\text{N} \] \[ \text{Total mass} = 1\text{kg} + 3\text{kg} = 4\text{kg} \] - Using Newton's
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