1+tan² (0) = sec²0 49+ 49 tan² (0) = 49 sec ²4 (0) 49 + ( 7 tan (0))² = (7 sec (0)) ² Let x-1=7 tan (0) dx = 7 sec² (0) do x = 7 tan(0) +1 s : 8x S √(x- 1)2 + 49 Your answer should not involve any trig. or inverse trig. functions. 8x dx = (x-1)² +49 +C dx 8(7 tan (0) +1) (7 sec²(0)) do √ (7 tan (0))² + 49
1+tan² (0) = sec²0 49+ 49 tan² (0) = 49 sec ²4 (0) 49 + ( 7 tan (0))² = (7 sec (0)) ² Let x-1=7 tan (0) dx = 7 sec² (0) do x = 7 tan(0) +1 s : 8x S √(x- 1)2 + 49 Your answer should not involve any trig. or inverse trig. functions. 8x dx = (x-1)² +49 +C dx 8(7 tan (0) +1) (7 sec²(0)) do √ (7 tan (0))² + 49
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
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Transcribed Image Text:1+tan² (0) = sec²0
49 + 49 tan² (0) = 49 sec ²4(0)
49 + (7 tan (0))²
(7 sec (0))²
Let x-1=7 tan (0)
/dx = 7 sec ² (0) do
x=7 tan (0) +1
Your answer should not involve any trig. or inverse trig. functions.
:
dx
√ √₁e=²13²+49d²=+C
V (x
=
S
8x
S
8x
) (x-1) ²³ +49
dx
8(7 tan (0) +1)
√ (7 tan (0))² + 49
(7 sec² (0)) do
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