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1+tan² (0) = sec²0 49+ 49 tan² (0) = 49 sec ²4 (0) 49 + ( 7 tan (0))² = (7 sec (0)) ² Let x-1=7 tan (0) dx = 7 sec² (0) do x = 7 tan(0) +1 s : 8x S √(x- 1)2 + 49 Your answer should not involve any trig. or inverse trig. functions. 8x dx = (x-1)² +49 +C dx 8(7 tan (0) +1) (7 sec²(0)) do √ (7 tan (0))² + 49

1+tan² (0) = sec²0 49+ 49 tan² (0) = 49 sec ²4 (0) 49 + ( 7 tan (0))² = (7 sec (0)) ² Let x-1=7 tan (0) dx = 7 sec² (0) do x = 7 tan(0) +1 s : 8x S √(x- 1)2 + 49 Your answer should not involve any trig. or inverse trig. functions. 8x dx = (x-1)² +49 +C dx 8(7 tan (0) +1) (7 sec²(0)) do √ (7 tan (0))² + 49

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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1+tan² (0) = sec²0 49 + 49 tan² (0) = 49 sec ²4(0) 49 + (7 tan (0))² (7 sec (0))² Let x-1=7 tan (0) /dx = 7 sec ² (0) do x=7 tan (0) +1 Your answer should not involve any trig. or inverse trig. functions. : dx √ √₁e=²13²+49d²=+C V (x = S 8x S 8x ) (x-1) ²³ +49 dx 8(7 tan (0) +1) √ (7 tan (0))² + 49 (7 sec² (0)) do
Transcribed Image Text:1+tan² (0) = sec²0 49 + 49 tan² (0) = 49 sec ²4(0) 49 + (7 tan (0))² (7 sec (0))² Let x-1=7 tan (0) /dx = 7 sec ² (0) do x=7 tan (0) +1 Your answer should not involve any trig. or inverse trig. functions. : dx √ √₁e=²13²+49d²=+C V (x = S 8x S 8x ) (x-1) ²³ +49 dx 8(7 tan (0) +1) √ (7 tan (0))² + 49 (7 sec² (0)) do
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