1R,2S-dibromocyclododecane from acetylene and anything with 10 carbons or less. To do this problem, you must realize that a 12-membered ring unlike cyclohexene can be Z or E. Think of cyclohexene which only exists as the "Z" form and what product it forms with Br2 or maybe better, 2-butene which has two possible diastereomers and which diastereomer would form 2R,3S-dibromobutane.

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Supply synthetic routes to the following molecules using the indicated starting materials

To synthesize 1R,2S-dibromocyclododecane from acetylene and any compound comprising 10 or fewer carbons, one must understand that a 12-membered ring, unlike cyclohexene, has the potential to exist in a Z or E configuration. Consider cyclohexene, which is restricted to the “Z” form. When reacted with Br₂, determine the outcome, or alternatively, examine 2-butene which presents two possible diastereomers. Identify which diastereomer leads to the formation of 2R,3S-dibromobutane.
Transcribed Image Text:To synthesize 1R,2S-dibromocyclododecane from acetylene and any compound comprising 10 or fewer carbons, one must understand that a 12-membered ring, unlike cyclohexene, has the potential to exist in a Z or E configuration. Consider cyclohexene, which is restricted to the “Z” form. When reacted with Br₂, determine the outcome, or alternatively, examine 2-butene which presents two possible diastereomers. Identify which diastereomer leads to the formation of 2R,3S-dibromobutane.
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