1o 10. A force is applied along the x-direction on a 5.00 kg object. The force varies along its path as shown in the graph. It lasts for 0.50 minute. Find (a) the net work done by the force on the object and (b) the average power the force delivered during that time. (N) (u)x 平 10. -5 -10

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Chapter1: Units, Trigonometry. And Vectors
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**Educational Content: Force and Work Done on an Object**

**Problem Statement:**
A force is applied along the x-direction on a 5.00 kg object. The force varies along its path as shown in the graph. It lasts for 0.50 minute. Find (a) the net work done by the force on the object and (b) the average power the force delivered during that time.

**Graph Explanation:**

The graph is a force-position (Fx vs. x) graph, which depicts how the force applied in the x-direction (Fx, in Newtons) varies as the object moves along the x-axis (x, in meters).

- The x-axis represents the position in meters ranging from -10 to 15.
- The y-axis represents the force in Newtons ranging from -10 to 10.
- The graph shows a line starting from a force of 10 N at 0 m, decreasing linearly through the origin and reaching -5 N at approximately 15 m.

**Key Observations:**

1. The force initially is positive and decreases linearly with displacement until it becomes negative.
2. The graph shows a point where the force crosses the x-axis, which indicates a transition from positive to negative force as the object moves through 5 meters.

**Calculations Required:**

- **Net Work Done (W):** To find the net work done, calculate the area under the force-position curve from 0 to 15 m.
- **Average Power (P_avg):** Divide the net work done by the time duration (0.50 minute, converted to seconds).

This scenario illustrates the concepts of variable forces, work-energy principles, and power in physics. Analyzing such problems enhances understanding of real-world applications of these principles.
Transcribed Image Text:**Educational Content: Force and Work Done on an Object** **Problem Statement:** A force is applied along the x-direction on a 5.00 kg object. The force varies along its path as shown in the graph. It lasts for 0.50 minute. Find (a) the net work done by the force on the object and (b) the average power the force delivered during that time. **Graph Explanation:** The graph is a force-position (Fx vs. x) graph, which depicts how the force applied in the x-direction (Fx, in Newtons) varies as the object moves along the x-axis (x, in meters). - The x-axis represents the position in meters ranging from -10 to 15. - The y-axis represents the force in Newtons ranging from -10 to 10. - The graph shows a line starting from a force of 10 N at 0 m, decreasing linearly through the origin and reaching -5 N at approximately 15 m. **Key Observations:** 1. The force initially is positive and decreases linearly with displacement until it becomes negative. 2. The graph shows a point where the force crosses the x-axis, which indicates a transition from positive to negative force as the object moves through 5 meters. **Calculations Required:** - **Net Work Done (W):** To find the net work done, calculate the area under the force-position curve from 0 to 15 m. - **Average Power (P_avg):** Divide the net work done by the time duration (0.50 minute, converted to seconds). This scenario illustrates the concepts of variable forces, work-energy principles, and power in physics. Analyzing such problems enhances understanding of real-world applications of these principles.
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