Answered: 1eV 1.6 x 1019 J Calculate the energy… | bartleby

Related questions

Question

100%

Speed of light in vaccum =
3 x 10° m/s
1eV
1.6 x 1019 J
1.
Calculate the energy of a photon of blue light, 1 = 450 nm.

Expert Solution

Step by step

Solved in 2 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

CO2 lasers can be used in cosmetic surgery. The wavelength of light emitted by a C02 laser is 10.6 micrometers (1 micrometer = 1 x 10^-6 m). a) What frequency is this in Hz and b) In what part of the spectrum is it?
25. A beam of 150-eV electrons falls on a powder nickel sample. Find the two smallest Bragg angles at which reflection takes place, recalling that Ni has an fec lattice with a cube edge equal to 3.25 Å.
2. When discussing Bragg scattering we showed that constructive interference between waves reflecting from Bragg planes occurs when Ar = 2d sin(0) = nλ where Ar was the path length difference, d was the spacing between Bragg planes, the angle between the incident motion (light ray or particle direction) and the Bragg plane, n an integer, and λ the wavelength of the light or deBroglie wave. When discussing the diffraction from a single crystal of Ni we expressed this condition for constructive interference as D sin(ø) = nλ, where D was the spacing between Ni atoms, and was the angle between particles shot perpendicular to a face of the Ni crystal and their reflection to a detector. The relation Φ between the angles is: 0 = and between the distances is d = D sin(). 2 (a) Using identity, e¹A cos(A) e¹A+e-iA 2 cos(A) + i sin(A), prove that sin(A) = where i = √-1 is an imaginary number. = = e¹A-e-iA 2i - (b) Using the identities from part (a) prove that sin(A - B) = sin(A) cos(B) – cos(A)…
If the resolution of a spectrograph is∆λ = 10-12 m, would it be able to separate the Kα lines for lead and bismuth? Explain.
An electron beam, where all electrons have the same energy of 42.5 eV, strikes perpendicularly on the surface of a crystalline material, causing electrons to scatter from the surface atoms. The order of diffraction m = 2 intensity maximum occurs at an angle of 60.6\ deg relative to the surface normal. a) Calculate the distance between atoms in the surface layer. d = b) Are there any other intensity maxima? 1) Yes. 2) No.
|An X-ray photon of 0.05 nm wavelength horizontally strikes a free, stationary electron, and the scattered photon departs at 90° from the initial photon direction. Determine the momentum of each of the following particles: incident photon, scattered photon and electron. 4.
What color would a photon with an energy of 2.175 eV be? 1 eV = 1.60218 x 10^-19 Red 700-635 nm Orange 635-590 nm Yellow 590-560nm Green 560-520nm Cyan 520-490nm Blue 490-450nm Violet 450-400nm
Xray light of wavelength 5.4 x 10-12m is incident on stationary electrons. Scattered light of wavelength 6.5x10-12m is detected at what scattering angle? Group of answer choices 56.9 deg 51.8 deg none of the above 24.9 deg 75 deg
Pls help ASAP.
Calculate the de Broglie wavelength of an electron moving with 1/3rd of the speed of light in vacuum. (Neglect relativistic effect) (Planck's constant : h = 6.63 × 10-34 Js, Mass of electrons : m = 9.11 × 10-28 g) %3D
X-rays of wavelength 0.0628 nm are scattered from a crystal with a grazing angle of 11.3°. Assume m = 1 for this process. Calculate the spacing between the crystal planes. d = nm
ASS 3. When light with a wavelength of 222 nm is incident on a certain metal surface, electrons are ejected with a maximum kinetic energy of 3.16 × 10-¹⁹ J. Determine the wavelength of light that should be used to quadruple the maximum kinetic energy of the electrons ejected from this surface. nm fo 0 ssf60€ ssf606 5 09588 09 ssf60 ssf60

SEE MORE QUESTIONS