MISSED THIS? Read SectionI Revie18.4 (Pages 803 - 817).A stoichiometrically equivalent amount of base is required to neutralizeKOH into volume using the concentration.19.0 mL of 0.128 M diprotic acid (H2 A) wastitrated with 0.1019 M KOH. The acid ionizationVolume KOH at first equivalence2.43 x 10-constants for the acid are K, = 5.2 x 10-5and K, = 3.4 x 10-10= 23.9 mLPart BAt what added volume of base does the second equivalence point occur?Express your answer to three significant figures.V =mLSubmitRequest Answer View Available Hint(s)V = 23.9 mLPrevious Answersv CorrectImportant: If you use this answer in later parts, use the full unroundecThe balanced equation for the neutralization of the diprotic acid occurs-

Moles of H2A = volume x concentration = 19.0/1000 x 0.126 = 0.002394 mol (A) At the first…

Answered: 19.0 mL of 0.128 M diprotic acid (H2 A)…

19.0 mL of 0.128 M diprotic acid (H2 A) was titrated with 0.1019 M KOH. The acid ionization constants for the acid are K = 5.2 x 10-5 and K = 3.4 × 10-10

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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