Homework Help is Here – Start Your Trial Now!
Math
Algebra
19. y =x is tangent to the circle S, y = 3x passes through the center (p, q) of S. the radius of the circle S is given by V2p D. /24 A.r = 3p B. r= 3q+ p C. r%D 20 The circle S with center (p, q) passes through the points (1, 1) and (2, 3). If a segment of the line y = x+2 is a diameter of S the value of P is: 1 А. 3 В. 2 С. 1 D. 21. An equation of a circle passing through the points (2, 1) and (-2, -1) as end points of a diameter is A. x2 + y2 - 2x - 4y -5 0 C. x2 + y2 - 4x + 2y +5 = 0 B. x2 + y2-5 = 0 D. x2 + y2 - 4x - 2y- 5 = 0

19. y =x is tangent to the circle S, y = 3x passes through the center (p, q) of S. the radius of the circle S is given by V2p D. /24 A.r = 3p B. r= 3q+ p C. r%D 20 The circle S with center (p, q) passes through the points (1, 1) and (2, 3). If a segment of the line y = x+2 is a diameter of S the value of P is: 1 А. 3 В. 2 С. 1 D. 21. An equation of a circle passing through the points (2, 1) and (-2, -1) as end points of a diameter is A. x2 + y2 - 2x - 4y -5 0 C. x2 + y2 - 4x + 2y +5 = 0 B. x2 + y2-5 = 0 D. x2 + y2 - 4x - 2y- 5 = 0

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
See similar textbooks
icon
Related questions
Question

Solve all Q19, 20, 21 explaining detailly each step

14. A point P moves so that its distance form the origin is always twice its distance form the point (1, 4). The equation of the locus of P is: A. x + y + 4x+ 16y – 34 = 0 B. 3x+ 3y – 8x – 32y + 68 = 0 C. 3x + 3y + 2x + 8y – 17= 0 D. x+ y + 2x + 8y + 17 = () 2 %3D | - 15. A point p moves so that it is at a constant distance of 5 units from the line 4x - 3y = 1. The possible set of positions of p is defined by the equațion: A. 4x – 3y = 26 and 4x – 3y = 24 B. 4x + 3y = 2 and 4x + 3y = 24 C. 4x + 3y = 26 and 4x - 3y + 24 = 0 %3D %3D %3D %3D D. 4x – 3y – 26 = 0 and 4x – 3y+ 24 = 0 %3D | 16. The points M (-1, 0), N (1,0) and P (x, y) are such that angle MPN is right angles. The equation of the locus of P is: 2 A. x + y - 2x - 4y – 4= 0 B. x+ y - 8x +1 = 0 C. x² + y- 1= 0 D. 2x + 2y – 20x – 3 = 0 | 15.The equation of a circle with center (-1, 2) and radius 3 is A. x+ y - 2x - 4y – 4 = 0 B. x² + y² + 2x – 4y - 4 = 0 C. x + y-x + 2y –9 = 0 16. The equation of the circle passing through the point (2, 7) with centre at (1, 3) is A. (x – 2)² + (y – 7)² = 17 C. (x – 1)² + (y – 3)² = 17 17.The equation of a circle of a circle with the points (-2, 2) and (3, 1) as ends of a diameter is: A. x + y - x - 3y – 4 = 0 B. x² + y² + x – y + 1 = 0 C. x + y – 2x + 3y – 5 = 0 D. x + y + 5x- 3y - 4 0 18. A circle with centre at point (3,4) touches the x-axis. Find the equation of the circle D. x + y + 2x - 4y +2 = 0 %3D %3D B. (x + 1)² + (y + 3)² = 17 D. (x - 3)2 + (y – 1)2 = 17 | B. (x – 4)2 + (y – 3)² = 25 D. (x- 3)2 + (y - 4)2 = 9 A. (x – 3)² + (y – 4)² = 25 C. (x – 3)2 + (3y – 4)² = 16 19. y =x is tangent to the circle S, y = 3x passes through the center (p, q) of S. the radius of the circle S is given by %3D D. 2q A. r = 3p B. r = 3q + p C.r= v2p 20.The circle S with center (p, q) passes through the points (1, 1) and (2, 3). If a segment of the line y = x+ 2 is a diameter of S the value of P is: А. 3 В. 2 С. 1 D. 2 21. An equation of a circle passing through the points (2, 1) and (-2, –1) as end points of a diameter is A. x2 + y? - 2x – 4y - 5 = 0 C. x2 + y2 – 4x + 2y + 5 = 0 22. The line y = 3x – 5 is a tangent to the circle x + y = 2ax = 0, The possible values of 'a' are B. x2 + y2 - 5 = 0 D. x² + y? – 4x – 2y – 5 = 0 %3D %3D | %3D %3D given by the equation A. 10a - 3a + 5 = 0 B. 91a+ 30a -25 = 0 C. a+ 30a + 25 = 0 D. a + 30a - 25=0 %3D 23. The line 3x - 4y + 14 is a tangent to the circle
Transcribed Image Text:14. A point P moves so that its distance form the origin is always twice its distance form the point (1, 4). The equation of the locus of P is: A. x + y + 4x+ 16y – 34 = 0 B. 3x+ 3y – 8x – 32y + 68 = 0 C. 3x + 3y + 2x + 8y – 17= 0 D. x+ y + 2x + 8y + 17 = () 2 %3D | - 15. A point p moves so that it is at a constant distance of 5 units from the line 4x - 3y = 1. The possible set of positions of p is defined by the equațion: A. 4x – 3y = 26 and 4x – 3y = 24 B. 4x + 3y = 2 and 4x + 3y = 24 C. 4x + 3y = 26 and 4x - 3y + 24 = 0 %3D %3D %3D %3D D. 4x – 3y – 26 = 0 and 4x – 3y+ 24 = 0 %3D | 16. The points M (-1, 0), N (1,0) and P (x, y) are such that angle MPN is right angles. The equation of the locus of P is: 2 A. x + y - 2x - 4y – 4= 0 B. x+ y - 8x +1 = 0 C. x² + y- 1= 0 D. 2x + 2y – 20x – 3 = 0 | 15.The equation of a circle with center (-1, 2) and radius 3 is A. x+ y - 2x - 4y – 4 = 0 B. x² + y² + 2x – 4y - 4 = 0 C. x + y-x + 2y –9 = 0 16. The equation of the circle passing through the point (2, 7) with centre at (1, 3) is A. (x – 2)² + (y – 7)² = 17 C. (x – 1)² + (y – 3)² = 17 17.The equation of a circle of a circle with the points (-2, 2) and (3, 1) as ends of a diameter is: A. x + y - x - 3y – 4 = 0 B. x² + y² + x – y + 1 = 0 C. x + y – 2x + 3y – 5 = 0 D. x + y + 5x- 3y - 4 0 18. A circle with centre at point (3,4) touches the x-axis. Find the equation of the circle D. x + y + 2x - 4y +2 = 0 %3D %3D B. (x + 1)² + (y + 3)² = 17 D. (x - 3)2 + (y – 1)2 = 17 | B. (x – 4)2 + (y – 3)² = 25 D. (x- 3)2 + (y - 4)2 = 9 A. (x – 3)² + (y – 4)² = 25 C. (x – 3)2 + (3y – 4)² = 16 19. y =x is tangent to the circle S, y = 3x passes through the center (p, q) of S. the radius of the circle S is given by %3D D. 2q A. r = 3p B. r = 3q + p C.r= v2p 20.The circle S with center (p, q) passes through the points (1, 1) and (2, 3). If a segment of the line y = x+ 2 is a diameter of S the value of P is: А. 3 В. 2 С. 1 D. 2 21. An equation of a circle passing through the points (2, 1) and (-2, –1) as end points of a diameter is A. x2 + y? - 2x – 4y - 5 = 0 C. x2 + y2 – 4x + 2y + 5 = 0 22. The line y = 3x – 5 is a tangent to the circle x + y = 2ax = 0, The possible values of 'a' are B. x2 + y2 - 5 = 0 D. x² + y? – 4x – 2y – 5 = 0 %3D %3D | %3D %3D given by the equation A. 10a - 3a + 5 = 0 B. 91a+ 30a -25 = 0 C. a+ 30a + 25 = 0 D. a + 30a - 25=0 %3D 23. The line 3x - 4y + 14 is a tangent to the circle
Expert Solution
steps

Step by step

Solved in 4 steps with 4 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Linear Equations
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:
9780134463216
Author:
Robert F. Blitzer
Publisher:
PEARSON
Contemporary Abstract Algebra
Contemporary Abstract Algebra
Algebra
ISBN:
9781305657960
Author:
Joseph Gallian
Publisher:
Cengage Learning
Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning
Algebra And Trigonometry (11th Edition)
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:
9780135163078
Author:
Michael Sullivan
Publisher:
PEARSON
Introduction to Linear Algebra, Fifth Edition
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:
9780980232776
Author:
Gilbert Strang
Publisher:
Wellesley-Cambridge Press
College Algebra (Collegiate Math)
College Algebra (Collegiate Math)
Algebra
ISBN:
9780077836344
Author:
Julie Miller, Donna Gerken
Publisher:
McGraw-Hill Education
SEE MORE TEXTBOOKS