19. (y² + 1) dx = y sec² x dy %3D

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Solve the given differential equations
In Problems 19–26 solve the given differential equation.
19. (y² + 1) dx = y sec² x dy
20. y(ln x – In y) dx = (x In x – x In y – y) dy
dy
+ 3x + 2y = 0
dx
21. (6x + 1)y² ·
dx
22.
dy
4y? + 6хy
Зу? + 2х
dQ
23. t
+ Q = t* In t
dt
24. (2x + y + 1)y' = 1
25. (х2 + 4) dy %3D (2х — 8ху) dx
26. (2r2 cos 0 sin 0 + r cos 0) de
+ (4r + sin 0 – 2r cos? 0) dr = 0
In Problems 27 and 28 solve the given initial-value problem
and give the largest interval I on which the solution is defined
dy
27. sin x
+ (cos x)y = 0, y(77/6) = -2
dx
dy
28.
+ 2(t + 1)y² = 0, y(0) = -
dt
29. (a) Without solving, explain why the initial-value
problem
dy
= Vy, y(xo) = yo
dx
has no solution for yo
(b) Solve the initial-value problem in part (a) for
yo >0 and find the largest interval I on which the
0.
solution is defined
30. (a) Find an implicit solution of the initial-value problem
dy
y²
y(1) = - V2.
dx
ху
(b) Find an explicit solution of the problem in part (a) and
give the largest interval I over which the solution is
defined. A graphing utility may be helpful here.
Transcribed Image Text:In Problems 19–26 solve the given differential equation. 19. (y² + 1) dx = y sec² x dy 20. y(ln x – In y) dx = (x In x – x In y – y) dy dy + 3x + 2y = 0 dx 21. (6x + 1)y² · dx 22. dy 4y? + 6хy Зу? + 2х dQ 23. t + Q = t* In t dt 24. (2x + y + 1)y' = 1 25. (х2 + 4) dy %3D (2х — 8ху) dx 26. (2r2 cos 0 sin 0 + r cos 0) de + (4r + sin 0 – 2r cos? 0) dr = 0 In Problems 27 and 28 solve the given initial-value problem and give the largest interval I on which the solution is defined dy 27. sin x + (cos x)y = 0, y(77/6) = -2 dx dy 28. + 2(t + 1)y² = 0, y(0) = - dt 29. (a) Without solving, explain why the initial-value problem dy = Vy, y(xo) = yo dx has no solution for yo (b) Solve the initial-value problem in part (a) for yo >0 and find the largest interval I on which the 0. solution is defined 30. (a) Find an implicit solution of the initial-value problem dy y² y(1) = - V2. dx ху (b) Find an explicit solution of the problem in part (a) and give the largest interval I over which the solution is defined. A graphing utility may be helpful here.
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