19. Two forces are acting on a block with F₁-25 N making an angle 0₁-37° with the horizontal and F₂-10 N making an angle 02-53° with the horizontal as shown. The two forces displace the block a horizontal distance of 2-5 m. What is the net work done in J on the block by the two forces? (a) 30 (b) 50 (c) 70 (d) 90 (e) 110 Tx
Q: When a 0.0598-kg golf ball takes off after being hit, its speed is 32.5 m/s. (a) How much work is…
A: Given dataMass of the ball m=0.0598kgspeed of the ball v=32.5 m/s
Q: A particle is subject to a force Fx that varies with position as shown in the following figure. Fx…
A: Please follow the steps below.Explanation:
Q: A block of mass m = 2.50 kg is pushed d = 2.70 m along a frictioniess horizontal table by a constant…
A:
Q: 13) A worker pushes a wheelbarrow with a horizontal force of 50 N on level ground over a distance of…
A: We know that W=F.s=Fs cos(theta)
Q: HW Ch 7 1.Two different forces F1 and F2 acts on an object as shown in Fig.F1=6i+7j and…
A:
Q: A block of mass m = 2.50 kg is pushed d = 2.30 m along a frictionless horizontal table by figure…
A:
Q: Consider the force F shown in the drawing. This force acts on an object that can move along the…
A: Write the expression for the work done.
Q: A particle moves along a straight path through displacement d= (8 m)iˆ + cjˆ while force F = (2 N)iˆ…
A:
Q: Four forces act on a crate of mass m = 1.0 kg, while it undergoes a displacement S, Calculate a) the…
A: Given Data : The weight of the block is given as w = 9.8 N. The magnitude of the force F on the…
Q: Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 95.0 kg, down a 0 =…
A: Given data: The total mass is m=95 kg. The inclination of slope is θ=70°. The coefficient of…
Q: A force (->f =->-6i+->2j-->5k) N acts on a particle that undergoes a displacement ->r=->-3+->4j m.…
A: a) The expression for find work done on the particle is W=F·r Substitute values in the above…
Q: As shown in the figure, the package of mass m = 3.00 kg initially resting at x = 0 on a roller belt…
A: Mass of the package is 3.00 kg
Q: A force ?⃗⃗acts in the x-direction, its magnitude given by ?=ax^3 where =2.0N/m^3. Find the work…
A: Equation of force Where
Q: Two different forces F1 and F2 acts on an object as shown in Fig. F1= 6i+7j+8k and F2 = 2i+3j+4k.The…
A:
Q: A box of mass 12.0 kg is pulled from rest up a 18.5 m long incline that makes an angle of 20.0° with…
A: Mass of box: m = 12 kg Length of inclined plane: s = 18.5 m Initial velocity of box: u = 0 FInal…
Q: A 980 kg car travels a distance of 6.00 m uphill along a road that makes an angle of 30.0∘ with the…
A: Mass of the car m = 980 kg.Distance is given as s = 6 m.Angle is given as Accelration of the car
Q: A force ~F=(6x5 N)i + (2y N)j acts between (x1,y1)= (2m, 3 m) to (x2; y2)=(3 m, 0 m).Calculate the…
A: Given : F =( 6x⁵ i + 2y j .)N x1= 2m , x2 = 3m y1= 3m ,y2= 0m We know…
Q: The force F = (3.37 N)i + (7.99 N)j acts on a particle as it moves along a straight line from…
A: The force acts on a particle is F→=3.37 Ni^+7.99 Nj^ The particle moves from a point 2.84 m, 0.81 m…
Q: Suppose the ski patrol lowers a rescue sled and victim, having a total mass of 95.0 kg, down a…
A:
Q: When a 0.0310-kg golf ball takes off after being hit, its speed is 44.4 m/s. (a) How much work is…
A:
Step by step
Solved in 2 steps
- An airplane flies 140 km at a constant altitude in a direction north of east. A wind is blowing that results in a net horizontal force on the plane due to the air of 2.40 kN in a direction 10.0° south of west. How much work is done by the air on the plane? Group of answer choices: A) -1.15 × 108 J B) -3.15 × 108 J C) 0.985 × 108 J D) -257 × 108 J E) 257 × 108 JThe force F(x,y) = [(2.56 N/m)y]i + [(3.14 N/m)x]j acts on a particle. What is the work done, in joules, by the force if the particle moves in a straight line from Cartesian coordinate (0.00 m, 0.00 m) to (4.39 m, 4.39 m)?A force of: F = (23i+16j-51K)N is applied to a particle of mass 15-kg. The particle has a speed of 10 m/s when the force is applied and is at coordinates: (6,-10,8)m. Under the application of this force. the particle moves to a new position: (25,-21,-10)m.Determine: a) The work done by the force on the particle over this interval b) The speed of the particle at the end of this interval
- A block of mass m = 3.00 kg is pushed a distance d = 6.30 m along a frictionless horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle 0 = 21.0° below the horizontal as shown in the figure below. m (a) Determine the work done on the block by the applied force. (b) Determine the work done on the block by the normal force exerted by the table. (c) Determine the work done on the block by the force of gravity. (d) Determine the work done by the net force on the block. JA force F = bx acts in the î-direction, where the value of b is 3.70 N/m³. How much work is done by this foPee in moving an object from (ro, Yo) = (0,0) to (xf, yf) = (2.60, 0) m? (A) O J (B) 11.4 J (C) 42.3 J (D) 56.4 J (E) 75.0 J (F) 169.1 JA dock worker pushes am = 2.20 kg bin a distance d = 2.40 m along the floor by a constant force of magnitude F = 16.0 N directed at an angle 0 = 20.0° below the horizontal as shown in the figure. Assume the floor is frictionless. (Enter your answers in joules.) (a) Determine the work done on the bin by the applied force (the force on the bin exerted by the dock worker). (b) Determine the work done on the bin by the normal force exerted by the floor. (c) Determine the work done on the bin by the gravitational force. (d) Determine the work dong by the net force on the bin.
- helpA block of mass m = 2.50 kg is pushed d = 2.80 m along a frictionless horizontal table by a constant applied force of magnitude F = 15.0 N directed at an angle 8 = 25.0° below the horizontal as shown in the figure below. m (a) Determine the work done by the applied force. (b) Determine the work done by the normal force exerted by the table. (c) Determine the work done by the force of gravity. J (d) Determine the work done by the net force on the block.A particle is subject to a force F, that varies with position as shown in the following figure. F, (N) 3 1 x (m) 2 4 6 8 10 12 14 16' (a) Find the work done by the force on the particle as it moves from x = 0 to x = 2.00 m. (b) Find the work done by the force on the particle as it moves from x = 5.00 m to x = 7.00 m. (c) Find the work done by the force on the particle as it moves from x = 10.0 m to x = 15.0 m. (d) What is the total work done by the force over the distance x = 0 to x = 15.0 m?
- The skateboarder in the figure is coasting down a ramp, and there are three forces acting on her: her weight W (magnitude = 699 N), a frictional force (magnitude = 189N) that opposes her motion, and a normal force FN (magnitude = 643 N). Determine the net work done (a) by the weight W, (b) by the frictional force 7, and (c) by the normal force when she coasts for a distance of 11.4 m. N 45 6 14m 23.0°/ W FN 0=67.0° 0 = 180.0° $5 Weight component (b) FN e = 90.0°A 13 N force with a fixed orientation does work on a particle as the particle moves through displacement à = (3î − 5ĵ + 3k) What is the angle between the force and the displacement if the change in the particle's kinetic energy is (a) +17.0 J and (b)-17.0 J? (a) Number i (b) Number i eTextbook and Media Units Units m.9. A particle is subject to a force F, that varies F, (N) with position as shown in the figure. Find the work done by the force on the particle as it 3 2 moves (a) from x = 0 to x = 5 m, (b) from 1 x = 5 m to x = 10 m, and (c) from x = 10 m to x = 15 m. x (m) 2 4 6. 8. 10 12 14 16