19. Obtain the eight incongruent solutions (a) 5x+3y = 1 (mod 7) 3x + 2y = 4 (mod 7). (b) 7x + 3y = 6 (mod 11) 4x + 2y = 9 (mod 11). (c) 11x + 5y = 7 (mod 20) 6x + 3y = 8 (mod 20).

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Chapter2: Second-order Linear Odes
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#20

Title: Solving Systems of Linear Congruences

---

**Page 84 - Elementary Number Theory**

**Problem 19**: Obtain the eight incongruent solutions of the linear congruence \(3x + 4y \equiv 5 \pmod{7}\).

**Problem 20**: Find the solutions of each of the following systems of congruences:

- (a) 
  \[
  \begin{aligned}
  5x + 3y &\equiv 1 \pmod{7} \\
  3x + 2y &\equiv 4 \pmod{7} \\
  \end{aligned}
  \]

- (b) 
  \[
  \begin{aligned}
  7x + 3y &\equiv 6 \pmod{11} \\
  4x + 2y &\equiv 9 \pmod{11} \\
  \end{aligned}
  \]

- (c) 
  \[
  \begin{aligned}
  11x + 5y &\equiv 7 \pmod{20} \\
  6x + 3y &\equiv 8 \pmod{20} \\
  \end{aligned}
  \]

---

**Explanation**:
In these problems, we are working on solving systems of linear congruences. Each system consists of two linear congruences that need to be solved simultaneously. The solutions provided will satisfy both congruences in each system under the given modulus.

The problems involve using the properties of congruences and often require methods such as substitution or the application of the Chinese Remainder Theorem to find the solutions within the specified modulus.
Transcribed Image Text:Title: Solving Systems of Linear Congruences --- **Page 84 - Elementary Number Theory** **Problem 19**: Obtain the eight incongruent solutions of the linear congruence \(3x + 4y \equiv 5 \pmod{7}\). **Problem 20**: Find the solutions of each of the following systems of congruences: - (a) \[ \begin{aligned} 5x + 3y &\equiv 1 \pmod{7} \\ 3x + 2y &\equiv 4 \pmod{7} \\ \end{aligned} \] - (b) \[ \begin{aligned} 7x + 3y &\equiv 6 \pmod{11} \\ 4x + 2y &\equiv 9 \pmod{11} \\ \end{aligned} \] - (c) \[ \begin{aligned} 11x + 5y &\equiv 7 \pmod{20} \\ 6x + 3y &\equiv 8 \pmod{20} \\ \end{aligned} \] --- **Explanation**: In these problems, we are working on solving systems of linear congruences. Each system consists of two linear congruences that need to be solved simultaneously. The solutions provided will satisfy both congruences in each system under the given modulus. The problems involve using the properties of congruences and often require methods such as substitution or the application of the Chinese Remainder Theorem to find the solutions within the specified modulus.
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