Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
![### Problem 19:
**Given:**
\( f(x) = 3x^2 - 15 \)
\( g(x) = 1 - \frac{2}{3}x \)
**Task:**
Find \( (f \circ g)(x) \) evaluated at \( x = 6 \).
**Choices:**
- A. 57
- B. 60
- C. -48
- D. -61
- E. All of the Above
- F. None of the Above
**Solution Explanation:**
1. **Compute \( g(6) \):**
\[
g(x) = 1 - \frac{2}{3} \times x
\]
Substitute \( x = 6 \):
\[
g(6) = 1 - \frac{2}{3} \times 6 = 1 - 4 = -3
\]
2. **Compute \( f(g(6)) = f(-3) \):**
\[
f(x) = 3x^2 - 15
\]
Substitute \( x = -3 \):
\[
f(-3) = 3(-3)^2 - 15 = 3 \times 9 - 15 = 27 - 15 = 12
\]
Therefore, the correct answer is **not listed as a choice** under options A to D, and does not fit the criteria for E.
**Answer:**
F. None of the Above](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F409cee4a-60f6-4aa4-afef-be7f51867a9b%2F2ae21381-8aab-46b3-b7af-fccd30194a39%2Fybeao1n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Problem 19:
**Given:**
\( f(x) = 3x^2 - 15 \)
\( g(x) = 1 - \frac{2}{3}x \)
**Task:**
Find \( (f \circ g)(x) \) evaluated at \( x = 6 \).
**Choices:**
- A. 57
- B. 60
- C. -48
- D. -61
- E. All of the Above
- F. None of the Above
**Solution Explanation:**
1. **Compute \( g(6) \):**
\[
g(x) = 1 - \frac{2}{3} \times x
\]
Substitute \( x = 6 \):
\[
g(6) = 1 - \frac{2}{3} \times 6 = 1 - 4 = -3
\]
2. **Compute \( f(g(6)) = f(-3) \):**
\[
f(x) = 3x^2 - 15
\]
Substitute \( x = -3 \):
\[
f(-3) = 3(-3)^2 - 15 = 3 \times 9 - 15 = 27 - 15 = 12
\]
Therefore, the correct answer is **not listed as a choice** under options A to D, and does not fit the criteria for E.
**Answer:**
F. None of the Above
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