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19. If angles ZABC and ZBCD are complimentary, and ZABC is equal to 81° which equation could be used to help find LBCD? a 81° + 2(ZABC) = 180° %3D b ZBDC+ZCBD = 90° %3D c 81° + ZBCD = 180° %3D d 81° + ZBCD = 90° %3D

19. If angles ZABC and ZBCD are complimentary, and ZABC is equal to 81° which equation could be used to help find LBCD? a 81° + 2(ZABC) = 180° %3D b ZBDC+ZCBD = 90° %3D c 81° + ZBCD = 180° %3D d 81° + ZBCD = 90° %3D

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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19. If angles ZABC and ZBCD are complimentary, and ZABC is equal to 81° which equation could be used to help find LBCD? a 81° +2(ZABC) = 180° b ZBDC + ZCBD = 90° c 81° + ZBCD = 180° d 81° + ZBCD = 90° Check it skip v SCRATCHPAD * Improve this question 6 GET A HINT 45°F A arch
Transcribed Image Text:19. If angles ZABC and ZBCD are complimentary, and ZABC is equal to 81° which equation could be used to help find LBCD? a 81° +2(ZABC) = 180° b ZBDC + ZCBD = 90° c 81° + ZBCD = 180° d 81° + ZBCD = 90° Check it skip v SCRATCHPAD * Improve this question 6 GET A HINT 45°F A arch
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