19. (I) Determine the magnitude and direction of the electric force on an electron in a uniform electric field of strength 2460 N/C that points due east.
19. (I) Determine the magnitude and direction of the electric force on an electron in a uniform electric field of strength 2460 N/C that points due east.
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please type out your solution so that it is easy to read I have bad eyesight
![### Problem 19
**Determine the magnitude and direction of the electric force on an electron in a uniform electric field of strength 2460 N/C that points due east.**
**Explanation:**
The text above asks to determine the magnitude and direction of the electric force on an electron when subjected to a uniform electric field. The specified electric field has a strength of \(2460 \, \text{N/C}\) and is directed due east.
**Solution Outline:**
1. **Electric Force Formula:**
The electric force (F) experienced by a charge (q) in an electric field (E) is given by:
\[
F = qE
\]
2. **Electric Charge of an Electron:**
The charge of an electron is \( -1.6 \times 10^{-19} \, \text{C} \).
3. **Calculation:**
Since the electric field points east and the electron has a negative charge, the direction of the force on the electron will be opposite to the direction of the electric field.
4. **Magnitude:**
\[
F = (-1.6 \times 10^{-19} \, \text{C}) \times (2460 \, \text{N/C})
\]
\[
F = -3.936 \times 10^{-16} \, \text{N}
\]
The magnitude of the force is \(3.936 \times 10^{-16} \, \text{N}\).
5. **Direction:**
The force will be directed due west because the electron is negatively charged and the electric field points due east.
**Summary:**
The magnitude of the electric force on the electron is \(3.936 \times 10^{-16} \, \text{N}\), and the direction of the force is due west.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F597e870a-d1dc-4e8b-ac25-38d259c0bf97%2Fa416cf43-6034-479a-8c0a-0cb148129af2%2Fw3lekx_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem 19
**Determine the magnitude and direction of the electric force on an electron in a uniform electric field of strength 2460 N/C that points due east.**
**Explanation:**
The text above asks to determine the magnitude and direction of the electric force on an electron when subjected to a uniform electric field. The specified electric field has a strength of \(2460 \, \text{N/C}\) and is directed due east.
**Solution Outline:**
1. **Electric Force Formula:**
The electric force (F) experienced by a charge (q) in an electric field (E) is given by:
\[
F = qE
\]
2. **Electric Charge of an Electron:**
The charge of an electron is \( -1.6 \times 10^{-19} \, \text{C} \).
3. **Calculation:**
Since the electric field points east and the electron has a negative charge, the direction of the force on the electron will be opposite to the direction of the electric field.
4. **Magnitude:**
\[
F = (-1.6 \times 10^{-19} \, \text{C}) \times (2460 \, \text{N/C})
\]
\[
F = -3.936 \times 10^{-16} \, \text{N}
\]
The magnitude of the force is \(3.936 \times 10^{-16} \, \text{N}\).
5. **Direction:**
The force will be directed due west because the electron is negatively charged and the electric field points due east.
**Summary:**
The magnitude of the electric force on the electron is \(3.936 \times 10^{-16} \, \text{N}\), and the direction of the force is due west.
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