19 With the usual notations, find p for a binomial random variable X if n = 6, and if 9 P ( X = 4) = P (X = 2) %3D
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- In a digital communication channel, assume that the number of bits received in error can be modeled by a binomial random variable, and assume that the probability that a bit is received in error is 0.0001. If 150,000 bits are transmitted, what is the probability that errors are between 10 and 18? How to compute P(X=10)= (150000c10)(0.0001)10(1-0.0001)150000-10Suppose 22% of students at a certain university are out of state students. A professor takes a random sample of 50 students. Let X = the number of out of state students in the sample. Determine if X is binomial by stating and checking all four requirements. If X is binomial, summarize the distribution of X in shorthand notation.Let the probability of winning a bet in a roulette game is 1/38.Find the probability of winning at least 1 time in 38 games with the Binomial formula and the Poisson's approximation to the Binomial distribution.
- For independent random variables X and Y, we have var(X -Y) = var(X)-var(Y ). * true FalseEight students attended a birthday party. Three of them were confirmed Covid-19 positive. The contact tracer had conducted a random test for only two students. Find the probability distribution for random variable X which represents the number of Covid-19 positive patients. What three statements of the problem can be concluded out of the topic Covid-19?I am confused when to use BinomPDF vs. BinomCDF; Find the probability that 17 or more of these 44 randomly-selected burials are babies. I know that from the probability is 13/51, I gathered this from the larger sample of data, however I do not know how to compute "or more"/"or fewer".
- Suppose we have a bucket of 20 balls with 10 red and 10 green. We take 5 draws and after each draw, we remove the chosen ball from the bucket before our next draw (this is called drawing without replacement). Can we use the binomial distribution to model this scenario? Why or why not?Assume that random guesses are made for 3 multiple-choice questions on a test with 2 choices for each question, so that there are n=3 trials, each with probability of success (correct) given by p=0.50. Find the probability of no correct answers.Use the normal approximation to the binomial to calculate the probability of getting more than 39 defectives in a random sample of 400 taken from a population which is 8% defective.