19) Determine the total pressure of the series of gases below: Po2 = 20.2 Kpa, PN2 = 46.7 Kpa, PHe = 26.7 Kpa a. Рт 3 9.36 Кра b. Рт%3D 936 Кра c. PT =9360 Kpa d. PT =93.6 Kpa 20) A soda bottle is flexible enough that th
19) Determine the total pressure of the series of gases below: Po2 = 20.2 Kpa, PN2 = 46.7 Kpa, PHe = 26.7 Kpa a. Рт 3 9.36 Кра b. Рт%3D 936 Кра c. PT =9360 Kpa d. PT =93.6 Kpa 20) A soda bottle is flexible enough that th
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
number 19
![18) Dalton's law equation is: B
a. Pr = P1 - P2 – P3..
b. Pr = P1+ P2 + P3..
c. Pr = P1 P2 ÷ P3..
d. Pr = P1 x P2 x P3..
19) Determine the total pressure of the series of gases below:
Po2 = 20.2 Kpa, PN2 = 46.7 Kpa, PHe = 26.7 Kpa
%3D
a. PT = 9.36 Kpa
b. PT=936 Kra
c. PT = 9360 Kpa
d. PT =93.6 Kra
%3D
20) A soda bottle is flexible enough that the volume of the bottle
have an empty soda bottle (volume of 2 L) at room temperatur
you put it in your freezer (-4 °C)? Use Charles' Law and SHO
V1=21 T1=(25+273.15)
K=298K
V2=? T2=(-4+273.15)
K=269K
V2=V1 X T2/T1 =21 Y ?601](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc6f813d1-160b-4ed2-85cf-5cf0e19a5fd7%2Fc877533b-750c-4546-96d1-e5574e10fa1c%2Fxmx8nqc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:18) Dalton's law equation is: B
a. Pr = P1 - P2 – P3..
b. Pr = P1+ P2 + P3..
c. Pr = P1 P2 ÷ P3..
d. Pr = P1 x P2 x P3..
19) Determine the total pressure of the series of gases below:
Po2 = 20.2 Kpa, PN2 = 46.7 Kpa, PHe = 26.7 Kpa
%3D
a. PT = 9.36 Kpa
b. PT=936 Kra
c. PT = 9360 Kpa
d. PT =93.6 Kra
%3D
20) A soda bottle is flexible enough that the volume of the bottle
have an empty soda bottle (volume of 2 L) at room temperatur
you put it in your freezer (-4 °C)? Use Charles' Law and SHO
V1=21 T1=(25+273.15)
K=298K
V2=? T2=(-4+273.15)
K=269K
V2=V1 X T2/T1 =21 Y ?601
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