19 25The Hill cipher with matrix 3 51447.11 was used to produce the following ciphertext:1.17RCJCCUFYEXNUHWMFind the message.

The following steps are used to decrypt the cipher text. Assign numbers from 0 to 25 for the…

Answered: 19 25 4 11 was used to produce the…

Algebra and Trigonometry (MindTap Course List)

4th Edition

ISBN:9781305071742

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter11: Matrices And Determinants

Section11.2: The Algebra Of Matrices

Problem 4E

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DONT USE AI, USE PENCIL AND PAPER WHILE DOING IT. SHOW ANSWER AND RESULTS An RSA cipher has public key pq = 65 and e = 7. (a) Translate the message YES into its numeric equivalent, and use the formula C = Me (mod pq) to encrypt the message.
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Use the RSA cipher with public key (n, e) = (713, 43) to encrypt the word "TEE." Start by encoding the letters of the word "TEE" into their numeric equivalents. Assume the letters of the alphabet are encoded as follows: A = 01, 8 = 02, C = 03, ..., Z = 26. Since the code for T is 20 and since e = 43 = 32 + 8 + 2 + 1, the first letter of the encrypted message is found by computing 2043 mod 713. 20¹a (mod 713) 20² Eb (mod 713) 204 c (mod 713) 208 d (mod 713) 2032 = f (mod 713) 2016 e (mod 713) b = The result is that a = C = d = e = and f = Thus, 2043 mod 713 = (a · b. d. f) mod 713 = So the first number in the encrypted message is Repeat these computations for each letter to find the complete encrypted message and enter your answer below. (Enter the message as a sequence of integer triples separated by a single space, where each triple is written using a fixed number of digits: 001 for 1, 002 for 2, ..., 099 for 99.)
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Alice received the following ciphertext from Bob, "08 01 08 05". Bob had encrypted it using the RSA cypher with Alice's public key (pq, e) = (55, 3), where p = 5 and q = 11. Note that (p − 1)(q − 1) = 40. The value for d in Alice's private key, (pq, d) is a positive inverse for 3 modulo (p − 1)(q − 1). It was found to be 27 in Examples 8.4.8(b) and 8.4.10. What is Bob's message after Alice decrypts it? (Assume Bob encoded one letter at a time using the encoding A = 01, 8 = 02, C = 03, ..., Z = 26.) To decrypt Bob's message, Alice uses the decryption formula M = C mod where M is the code for a letter of the message, C is the encrypted version of the letter, (pq, e) = (55, 3) is the public key, and (pq, d) = (55, 27) is the private key. (a) To begin, Alice computes the values of a, b, c, d and e that are indicated below. 084 c (mod 55) 08¹ = a (mod 55) 088 d (mod 55) She finds that a = 082 b (mod 55) 0816e (mod 55) b = , C = d= and e = Because 27 = 16 + 8 + 2 + 1, 0827= 0816 +8+2+1 =…
In the use of RSA Cryptography, for the public key (11, 65), what is the decrypted original message for ciphertext 5? You must show every step from beginning until the end for the derivation of the message.
please find the value for a,b,c,d,e,f,g,h,i

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19 25 4 11 was used to produce the following ciphertext: 17 The Hill cipher with matrix 3 14 RCJCCUFYEXNUHWM Find the message.