19-20. The oxidation of phosphine (PH3) to phosphorus pentoxide (P205) is given by the chemical equation: 2PH3 + 402 P2O5 + 3H2O 19. If the reaction gives 64% yield, how many grams of PH3 should be used to give an actual yield of 250 grams of P2O5? A. 188 g C. 187 g B. 189 g D. 186 g 20. How many grams of P2O5 will be produced in the reaction? A. 73.1 g P2O5 C. 74.1 g P2O5 B. 72.1 g P205 D. 75.1 g P20s

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The oxidation of phosphine (PH3) to phosphorus pentoxide (P2O5) is given by the balanced chemical equation:

2PH3 + 4O2 -> P2O5 + 3H2O

19. If the reaction gives a 64% yield, how many grams of PH3 should be used to give an actual yield of 250 grams of P2O5?

20. How many grams of P2O5 will be produced in the reaction?

19-20. The oxidation of phosphine (PH3) to phosphorus pentoxide (P205) is given by
the chemical equation: 2PH3 + 402 P2Os + 3H2O
19. If the reaction gives 64% yield, how many grams of PH3 should be used to give an
actual yield of 250 grams of P2O5?
A. 188 g
C. 187 g
B. 189 g
D. 186 g
20. How many grams of P205 will be produced in the reaction?
A. 73.1 g P205
C. 74.1 g P2O5
B. 72.1 g P205
D. 75.1 g P2Os
Transcribed Image Text:19-20. The oxidation of phosphine (PH3) to phosphorus pentoxide (P205) is given by the chemical equation: 2PH3 + 402 P2Os + 3H2O 19. If the reaction gives 64% yield, how many grams of PH3 should be used to give an actual yield of 250 grams of P2O5? A. 188 g C. 187 g B. 189 g D. 186 g 20. How many grams of P205 will be produced in the reaction? A. 73.1 g P205 C. 74.1 g P2O5 B. 72.1 g P205 D. 75.1 g P2Os
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