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180 mL of a 2.85 M NaNO3 solution Express your answer using three significant figures. Hν ΑΣφ ? m =

180 mL of a 2.85 M NaNO3 solution Express your answer using three significant figures. Hν ΑΣφ ? m =

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate the grams of solute needed to prepare each of the following solutions.

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180 mL of a 2.85 M NaNO3 solution Express your answer using three significant figures. Hν ΑΣφ ? m = g NaNO3 Submit Request Answer
Transcribed Image Text:180 mL of a 2.85 M NaNO3 solution Express your answer using three significant figures. Hν ΑΣφ ? m = g NaNO3 Submit Request Answer
6.5 L of a 0.50 M CaCl2 solution Express your answer using two significant figures. Hν ΑΣφ ? Xb b |X| X•10" 9.0 • 102 g CaCl2 m = Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining 圓 18
Transcribed Image Text:6.5 L of a 0.50 M CaCl2 solution Express your answer using two significant figures. Hν ΑΣφ ? Xb b |X| X•10" 9.0 • 102 g CaCl2 m = Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining 圓 18
Expert Solution
Step 1

By help of Following formula we can calculate the mass of solute used in preparation of solution -

Mass of solute = Molarity×Molar mass of solute×Volume of solution in mL/1000

 

 

(1) Given here , Molarity = 2.85 M NaNO3

Molar mass of NaNO3 = 84.9947 g/mol

Volume = 180 mL

Then, from above formula -

Mass of solute = 2.85×84.9947×180/1000

Mass of solute = 43.6 g NaNO3

 

Therefore, mass of NaNO3 is 43.6 g.

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