18.8 NuttyKorn is a snack consisting of caramel popcorn and peanuts. They advertisethat the weight of peanuts (in ounces) in a 26-ounce box of snack follows a normaldistribution with mean 5 and standard deviation .2.A consumer group has grave fears that NuttyKorn is skimping on the peanuts.They want to test Họ : µ = 5 versus Ha : µ < 5, where µ is the true averageweight of peanuts in a 26-ounce box of snack. (Assume that the standard deviationis known to be 0.2.) They will randomly select four boxes and reject Ho if at leastthree of the boxes have less than 4.8 ounces of peanuts.(a) What is the test size for this decision rule? (Use the 68-95-99.7 rule.)(b) Suppose that the true average weight of peanuts is only µ = 4.6 ounces (andthe standard deviation is again .2). What is the power of the test?

Given information: μ=5, σ=0.2 The Empirical Rule states that 99.7% of data observed following a…

Answered: 18.8 NuttyKorn is a snack consisting of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose that a Normal model describes furl economy (mile per gallon) for automobile and that a Saturn has a standardized score ( z score) of +2.2. This meatn taht Satturn.... gets 2.2 miler sper gallon. get 2.2 times the gas mileage of the avereage car. get 2.2 mpg more than the average car. have a standard deviation of 2.2 mpg achieve fuel eceonomy that is 2.2 standard deviations better thean the average car.
Diabetes Plasma-glucose levels are used to determine the pres- ence of diabetes. Suppose the mean In (plasma-glucose) concentration (mg/dL) in 35- to 44-year-olds is 4.86 with standard deviation = 0.54. A study of 100 sedentary people in this age group is planned to test whether they have a higher or lower level of plasma glucose than the general population. 7.7 If the expected difference is 0.10 In units, then what is the power of such a study if a two-sided test is to be used with a = .05? 7.8 Answer Problem 7.7 if the expected difference is 0.20 In units. 7.9 How many people would need to be studied to have 80% power under the assumptions in Problem 7.7?
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Steel rods are manufactured with a mean length of 22 centimeter (cm). Because of variability in the manufacturing process, the lengths of the rods are approximately normally distributed with a standard deviation of 0.06 cm. Click the icon to view a table of areas under the normal curve. (a) What proportion of rods has a length less than 21.9 cm? 0.0475 (Round to four decimal places as needed.) (b) Any rods that are shorter than 21.86 cm or longer than 22.14 cm are discarded. What proportion of rods will be discarded? 0.0196 (Round to four decimal places as needed.) (c) Using the results of part (b), if 5000 rods are manufactured in a day, how many should the plant manager expect to discard? 98 (Use the answer from part b to find this answer. Round to the nearest integer as needed.) (d) If an order comes in for 10,000 steel rods, how many rods should the plant manager expect to manufacture if the order states that all rods must be between 21.9 cm and 22.1 cm? (Round up to the nearest…
Steel rods are manufactured with a mean length of 26centimeter (cm). Because of variability in the manufacturing process, the lengths of the rods are approximately normally distributed with a standard deviation of 0.05 cm. Complete parts (a) to (d). (a) What proportion of rods has a length less than 25.9cm?
I wanted to do a market research study estimating the average hourly wage earned by childcare workers in the bay area. How large does my sample need to be in order to have a margin of error that is less than $0.50 with a 95% confidence in the result. Assume that the standard deviation of the wages is $2 per hour.
Low-density lipoprotein, or LDL, is the main source of cholesterol buildup and blockage in the arteries. This is why LDL is known as "bad cholesterol." LDL is measured in milligrams per deciliter of blood, or mg/dL. In a population of adults at risk for cardiovascular problems, the distribution of LDL levels is normal, with a mean of 123 mg/dL and a standard deviation of 41 mg/dL. If an individual's LDL is at least 1 standard deviation or more above the mean, he or she will be monitored carefully by a doctor. What percentage of individuals from this population will have LDL levels 1 or more standard deviations above the mean? Use the 68–95–99.7 rule. (Enter your exact answer as a whole number.) percentage %
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