18. If the acetic acid dissociation constant is Ka-1.8 X 10 and its concentration before dissolution is( 0.34M), the concentration of [H ] in an acid solution is equal to the following equation CH3COOH CH;COO +H* A) 3.52X103 B) 2.47X103 C) 3.52X105 D) 2.47X105

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Solve 18,19,and 20 No steps needed
18. If the acetic acid dissociation constant is Ka= 1.8 X 105 and its concentration
before dissolution is( 0.34M), the concentration of [H ] in an acid solution is
equal to the following equation
CH3COOH CH;COO +H*
A) 3.52X103
B) 2.47X103
C) 3.52X105
D) 2.47X105
19. If K-0.45 at a (150°C) for the equilibrium reaction:
%3D
N2 (g)+ O2 (g)
2NO
The Ke of the reaction is :
A) 0.45
B) 0.54
C) 0.69
D) 0.96.
20. If K= (0.92) at a (150°C) for the equilibrium reaction:
CO(g)+ 3H>(g) +
CH:(g)
+ H2O(g)
The K. of the reaction is :
A) 1106.86
B) 2.32 x104
C) 4.20 x105
D) 3.29 x 10-5 .
Transcribed Image Text:18. If the acetic acid dissociation constant is Ka= 1.8 X 105 and its concentration before dissolution is( 0.34M), the concentration of [H ] in an acid solution is equal to the following equation CH3COOH CH;COO +H* A) 3.52X103 B) 2.47X103 C) 3.52X105 D) 2.47X105 19. If K-0.45 at a (150°C) for the equilibrium reaction: %3D N2 (g)+ O2 (g) 2NO The Ke of the reaction is : A) 0.45 B) 0.54 C) 0.69 D) 0.96. 20. If K= (0.92) at a (150°C) for the equilibrium reaction: CO(g)+ 3H>(g) + CH:(g) + H2O(g) The K. of the reaction is : A) 1106.86 B) 2.32 x104 C) 4.20 x105 D) 3.29 x 10-5 .
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