18. An isosceles triangle has an area of 100 in²f the base is 20 in, what is the length of each leg? Round the answer to the nearest tenth. Work: Length of each leg: Work: 19. A kite has diagonals 6.2 and 8 ft. What is the area of the kite? Area: in f₁²

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### Geometry Problems

#### Problem 18:
**Question:** 
An isosceles triangle has an area of 100 in². If the base is 20 in, what is the length of each leg? Round the answer to the nearest tenth.

**Solution Approach:**
1. **Calculate the height of the triangle** using the formula for the area of a triangle: \( A = \frac{1}{2} \times \text{base} \times \text{height} \).
2. **Use Pythagorean theorem** to find the length of each leg of the isosceles triangle.

**Work Area:** 
- The height (h) of the triangle: 
  \[ 100 = \frac{1}{2} \times 20 \times h \implies h = \frac{100 \times 2}{20} = 10 \, \text{inches} \]
- With the height, use the Pythagorean theorem \((\text{leg})^2 = (\text{height})^2 + \left(\frac{\text{base}}{2}\right)^2\):
  \[ (\text{leg})^2 = 10^2 + 10^2 = 100 + 100 \implies \text{leg} = \sqrt{200} = 14.1 \, \text{inches} \]

**Answer:**
\[ \text{Length of each leg: } 14.1 \, \text{in} \]

#### Problem 19:
**Question:** 
A kite has diagonals of 6.2 ft and 8 ft. What is the area of the kite?

**Solution Approach:**
1. **Calculate the area of the kite** using the formula for the area of a kite: \( A = \frac{1}{2} \times d1 \times d2 \).

**Work Area:** 
- Using the given diagonals:
  \[ A = \frac{1}{2} \times 6.2 \times 8 \]
  \[ A = \frac{1}{2} \times 49.6 = 24.8 \, \text{ft}^2 \]

**Answer:**
\[ \text{Area: } 24.8 \, \text{ft}^2 \]

These problems involve fundamental
Transcribed Image Text:### Geometry Problems #### Problem 18: **Question:** An isosceles triangle has an area of 100 in². If the base is 20 in, what is the length of each leg? Round the answer to the nearest tenth. **Solution Approach:** 1. **Calculate the height of the triangle** using the formula for the area of a triangle: \( A = \frac{1}{2} \times \text{base} \times \text{height} \). 2. **Use Pythagorean theorem** to find the length of each leg of the isosceles triangle. **Work Area:** - The height (h) of the triangle: \[ 100 = \frac{1}{2} \times 20 \times h \implies h = \frac{100 \times 2}{20} = 10 \, \text{inches} \] - With the height, use the Pythagorean theorem \((\text{leg})^2 = (\text{height})^2 + \left(\frac{\text{base}}{2}\right)^2\): \[ (\text{leg})^2 = 10^2 + 10^2 = 100 + 100 \implies \text{leg} = \sqrt{200} = 14.1 \, \text{inches} \] **Answer:** \[ \text{Length of each leg: } 14.1 \, \text{in} \] #### Problem 19: **Question:** A kite has diagonals of 6.2 ft and 8 ft. What is the area of the kite? **Solution Approach:** 1. **Calculate the area of the kite** using the formula for the area of a kite: \( A = \frac{1}{2} \times d1 \times d2 \). **Work Area:** - Using the given diagonals: \[ A = \frac{1}{2} \times 6.2 \times 8 \] \[ A = \frac{1}{2} \times 49.6 = 24.8 \, \text{ft}^2 \] **Answer:** \[ \text{Area: } 24.8 \, \text{ft}^2 \] These problems involve fundamental
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