18. A formula for the focal length / of a convex lens 11.1 7-== -+-When f-4 and #-6, vis: a=6, 1 (a)-2 (b) 12 (c) (4)- 19. The quadratic equation in x whose roots are-2 and +5 is: (a) x²-3x-10=0 (b) x²+7x+10=0 (c) x² + 3x-10-0 (d) x²-7x-10-0 20. 8x²+13x-6=(x+p)(qx-3). The values of p and q are: (a) p=-2. q=4 (b) p-3.4-2 (c) p-2. q-8 (d) p-1.q-8 21. log168 is equal to: 26. (a) (b) 144 (c) 22. If log x=3 then: (a)x=8 (b)x= (c)x=9 (d)x= 23. (x²-x²-x+1) divided by (x-1) gives: (a) x²-x-1 (b)x¹+1 (c) x²-1 (d) x²+x-1 (d) 2 Which of the straight lines shown in Figure M4.5 has the equation y+4= 2x? (a) (iv) (b)(ii) (c)(iii) (d) (i) In de 6 A 61 (1) Figure M4.5 6x -6 (40) B 0/2 (M) In the right-angled triangle ABC shown in Figure M5.1, sine A is given by: (a) b/a (b) c/b (c) b/c (d) a/b Figure MS.1 27. In the right-angled triangle ABC shown in Figure MS.1, cosine C is given by: (a) a/b (b)c/b (c) a/c (d) b/a 25. 30. The equation of the graph shown in Figure M4.4 is: (a) x(x+1)= (b) 4x²-4x-15=0 (c) x²-4x-5=0 (d) 4x²+4x-15=0 Figure M4.4 3x 3 cm 15 h Q Figure M5.3 yo 15 10 -2 -1 0 1 -5 -10 -15 -20 radians is equivalent to: (a) 135 (b) 270 (c) 45° (d) 67.5° 5 L For the right-angled triangle PQR shown in Figure M5.3, angle R is equal to: (a) 41.41 (b) 48.59 (c) 36.87° (d) 53.13° Figure M5.2 2/3 4 cm In the triangular template ABC shown Figure M5.2, the length AC is: (a) 6.17 cm (b) 11.17 cm (c) 9.22 cm (d) 12.40 cm 8.30 cm R 42

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve all for me dont say it multiple ask questions. Solve all only correct options no need explanation please solve All i will Upvote thanks. Just need correct answer no explanation ok . Suggest to best maths expert can solve All
18. A formula for the focal length f of a convex lens
111
is = + - When f = 4 and u=6, vis:
(a)-2 (b) 12 (c)
19. The quadratic equation in x whose roots are-2 and
+5 is:
(a) x²-3x-10=0
(b) x² +7x+10=0
(c) x² + 3x-10=0 (d) x²-7x-10=0
20. 8x²+13x-6=(x+p)(qx-3). The values of p
and q are:
(a) p=-2.q=4
(b) p 3, q-2
(c) p=2.q=8
(d) p=1, q=8
21. log168 is equal to:
(a) (b) 144 (c) (d) 2
22. If log₂x=3 then:
(a)x=8 (b)x= (c)x=9 (d)x=
23. (x-x²-x+1) divided by (x - 1) gives:
(a) x²-x-1 (b) x² +1
(c) x²-1
(d) x²+x-1
28
Which of the straight lines shown in Figure M4.5
has the equation y+4= 2x?
(a) (iv) (b) (ii) (c) (iii) (d) (i)
+f
++
-6
0
(0)
y
()
Figure M4.5
с
Figure MS.1
4
26. In the right-angled triangle
Figure M5.1, sine A is given by:
6 A -6
b
-6
(10)
01/2 6 x
1st
(a) b/a (b) c/b (c) b/c (d) a/b
A
B
(N)
ABC shown in
27. In the right-angled triangle ABC shown in
Figure M5.1, cosine C is given by:
(a) a/b (b)c/b (c) a/c (d) b/a
25.
30.
The equation of the graph shown in Figure M4.4
is:
(a) x(x+1)=7
(b) 4x²-4x-15=0
(c) x²-4x-5-0
(d) 4x²+4x15=0
Figure M4.4
3x
3 cm
n
Q
15
radians is equivalent to:
(a) 135° (b) 270° (c) 45° (d) 67.5°
Figure M5.3
For the right-angled triangle PQR shown in
Figure M5.3, angle R is equal to:
(a) 41.41° (b) 48.59 (c) 36.87° (d) 53.13°
B
YA
-2 -1 0 1 2 3 x
-5
-10t
15
10
5
Figure M5.2
-15
-20+
4 cm
In the triangular template ABC shown in
Figure M5.2, the length AC is:
(a) 6.17 cm
(c) 9.22 cm
(b) 11.17 cm
(d) 12.40 cm
8.30 cm
R
42
C
Transcribed Image Text:18. A formula for the focal length f of a convex lens 111 is = + - When f = 4 and u=6, vis: (a)-2 (b) 12 (c) 19. The quadratic equation in x whose roots are-2 and +5 is: (a) x²-3x-10=0 (b) x² +7x+10=0 (c) x² + 3x-10=0 (d) x²-7x-10=0 20. 8x²+13x-6=(x+p)(qx-3). The values of p and q are: (a) p=-2.q=4 (b) p 3, q-2 (c) p=2.q=8 (d) p=1, q=8 21. log168 is equal to: (a) (b) 144 (c) (d) 2 22. If log₂x=3 then: (a)x=8 (b)x= (c)x=9 (d)x= 23. (x-x²-x+1) divided by (x - 1) gives: (a) x²-x-1 (b) x² +1 (c) x²-1 (d) x²+x-1 28 Which of the straight lines shown in Figure M4.5 has the equation y+4= 2x? (a) (iv) (b) (ii) (c) (iii) (d) (i) +f ++ -6 0 (0) y () Figure M4.5 с Figure MS.1 4 26. In the right-angled triangle Figure M5.1, sine A is given by: 6 A -6 b -6 (10) 01/2 6 x 1st (a) b/a (b) c/b (c) b/c (d) a/b A B (N) ABC shown in 27. In the right-angled triangle ABC shown in Figure M5.1, cosine C is given by: (a) a/b (b)c/b (c) a/c (d) b/a 25. 30. The equation of the graph shown in Figure M4.4 is: (a) x(x+1)=7 (b) 4x²-4x-15=0 (c) x²-4x-5-0 (d) 4x²+4x15=0 Figure M4.4 3x 3 cm n Q 15 radians is equivalent to: (a) 135° (b) 270° (c) 45° (d) 67.5° Figure M5.3 For the right-angled triangle PQR shown in Figure M5.3, angle R is equal to: (a) 41.41° (b) 48.59 (c) 36.87° (d) 53.13° B YA -2 -1 0 1 2 3 x -5 -10t 15 10 5 Figure M5.2 -15 -20+ 4 cm In the triangular template ABC shown in Figure M5.2, the length AC is: (a) 6.17 cm (c) 9.22 cm (b) 11.17 cm (d) 12.40 cm 8.30 cm R 42 C
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