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18. 2x² - 3y³ = 5; (-2,1)

18. 2x² - 3y³ = 5; (-2,1)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How do you solve number 18?
https://plus.pearson.com/courses/triebold41691/products/144553/pages/381 1. x² + 2xy = 3y- 3. x² - y² = 16. 5. y³ = x5 7. x²y³ + x³y = 11 9. ey + y² = 3x 11. ln(x² + y) = 2x + 1 13. e²y + x = ln y Chapter 3: Application 2. 2xy + 5 = 0 4. x² + y² = 25 6. y5 = x3 8. x³y2 + x³y3 = -19 10. ey - y³ = x² 12. 3 - x² = ln(x + y³) 14. e³y + 4x³ = 2 In y Differentiate implicitly to find dy/dx. Then find the slope of the curve at the given point. 15. 3x² - y² = 8; (2,4) 16. x³ + 2y³ = 6; (2,−1) 17. 2x³ + 4y² = −12; (−2,−1) 18. 2x² - 3y³ = 5; (−2,1) √3 19. x² + y² = 1; (1-1/³) 20. x² - y² = 1; (√3, √2) 359
Transcribed Image Text:https://plus.pearson.com/courses/triebold41691/products/144553/pages/381 1. x² + 2xy = 3y- 3. x² - y² = 16. 5. y³ = x5 7. x²y³ + x³y = 11 9. ey + y² = 3x 11. ln(x² + y) = 2x + 1 13. e²y + x = ln y Chapter 3: Application 2. 2xy + 5 = 0 4. x² + y² = 25 6. y5 = x3 8. x³y2 + x³y3 = -19 10. ey - y³ = x² 12. 3 - x² = ln(x + y³) 14. e³y + 4x³ = 2 In y Differentiate implicitly to find dy/dx. Then find the slope of the curve at the given point. 15. 3x² - y² = 8; (2,4) 16. x³ + 2y³ = 6; (2,−1) 17. 2x³ + 4y² = −12; (−2,−1) 18. 2x² - 3y³ = 5; (−2,1) √3 19. x² + y² = 1; (1-1/³) 20. x² - y² = 1; (√3, √2) 359
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