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18 -S x+3 dx = lim [SI 9-3 -S x+3 b-3* = lim a-3 18 9 1₁-0 dx = x+3 -5 (If the integral does not exist, enter 'DNE'.) •Discontinuous at x = -3 9 + lim 18 lim b-3+ 9 x+3 () () a+3 (-5)+3 18+3 b+3 Use FTC 2 JUse

18 -S x+3 dx = lim [SI 9-3 -S x+3 b-3* = lim a-3 18 9 1₁-0 dx = x+3 -5 (If the integral does not exist, enter 'DNE'.) •Discontinuous at x = -3 9 + lim 18 lim b-3+ 9 x+3 () () a+3 (-5)+3 18+3 b+3 Use FTC 2 JUse

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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18 -S x+3 dx = = lim 9 [SIA -S x+3 9-3 18 lim a-3 9 1₁-0 dx = x+3 -5 (If the integral does not exist, enter 'DNE'.) ·Discontinuous at x = -3 + lim b-3* 18 lim b-3+ 9 x+3 () () a+3 (-5)+3 18+3 b+3 Use FTC 2 juse
Transcribed Image Text:18 -S x+3 dx = = lim 9 [SIA -S x+3 9-3 18 lim a-3 9 1₁-0 dx = x+3 -5 (If the integral does not exist, enter 'DNE'.) ·Discontinuous at x = -3 + lim b-3* 18 lim b-3+ 9 x+3 () () a+3 (-5)+3 18+3 b+3 Use FTC 2 juse
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